Key Concept: Fast Multiplication Using Distributive Property

b) 461267
[Solution Description]
To multiply $4567 \times 101$, apply the distributive property:
$4567 \times 101 = 4567 \times (100 + 1) = 456700 + 4567 = 461267$

Key Concept: Fast Multiplications Using the Distributive Property

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion is true because using the distributive property simplifies multiplication of large numbers by breaking them into addition of shifted numbers (e.g., $3874 \times 11 = 38740 + 3874$). The reason is also true as it correctly defines the distributive property. Moreover, the reason provides the mathematical basis for the assertion, making it the correct explanation.

Key Concept: Distributive Property, Fast Multiplication

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
Let us verify the assertion step by step:
1. Using the distributive property: $2468 \times 11 = 2468 \times (10 + 1) = 24680 + 2468$
2. Add these two results:
$$ \\ 24680 + 2468 = 27148$$
3. Hence, the assertion is true as $2468 \times 11 = 27148$.
4. Now let's check the reason: For a 4-digit number $abcd \times 11$, the calculation follows the pattern:
$$ \\ a \, (a + b) \, (b + c) \, (c + d) \, d$$
5. For $2468 \times 11$:
$2$ (thousands), $2 + 4 = 6$ (hundreds), $4 + 6 = 10$ (tens, carry over 1 to hundreds), $6 + 8 = 14$ (units, carry over 1 to tens). Final digits are adjusted with carry-over:
Thousands: $2$
Hundreds: $6 + 1 (\text{carry}) = 7$
Tens: $0 + 1 (\text{carry}) = 1$
Units: $4$
Extending it further with the last digit $8$ gives $27148$.
6. The reason correctly explains the pattern and how the digits are derived, including handling of carry-over. Thus, both assertion and reason are true, and the reason correctly explains the assertion.

Key Concept: Distributive Property, Fast Multiplication

b) $abcde \times (100 + 1) = abcde \times 100 + abcde \times 1$
[Solution Description]
To multiply a 5-digit number $abcde$ by 101, we can use the distributive property:
$abcde \times 101 = abcde \times (100 + 1) = abcde \times 100 + abcde \times 1$
This simplifies to:
$abcde00 + abcde = abcde00 + abcde$
The result is obtained by shifting the original number left by two digits and adding the original number.

Key Concept: Distributive Property, Fast Multiplication

c) 27148
[Solution Description]
To find $2468 \times 11$, we can break it down using the distributive property:
$2468 \times 11 = 2468 \times (10 + 1) = 24680 + 2468$
Now, perform the addition:
$24680 + 2468 = 27148$
So, $2468 \times 11 = 27148$.

Key Concept: Fast Multiplication Using Distributive Property

b) 1353
[Solution Description]
To solve $123 \times 11$, we can use the distributive property:
$123 \times 11 = 123 \times (10 + 1) = 1230 + 123 = 1353$

Key Concept: Fast Multiplication Using Distributive Property

c) 8679
[Solution Description]
Using the distributive property for $789 \times 11$:
$789 \times 11 = 789 \times (10 + 1) = 7890 + 789 = 8679$

Key Concept: Distributive Property, Fast Multiplication, Error Analysis

a) Used $1357 \times (10 + 1)$ instead of $1357 \times (100 + 1)$
[Solution Description]
The correct calculation for $1357 \times 101$ using the distributive property is:
$1357 \times 101 = 1357 \times (100 + 1) = 135700 + 1357 = 137057$
The student's answer was $136907$, which is incorrect. The mistake likely occurred because the student might have added $1357$ to $13570$ instead of $135700$, i.e., they used $1357 \times (10 + 1)$ instead of $1357 \times (100 + 1)$.

Key Concept: Fast Multiplication Using Distributive Property

b) 8679
[Solution Description]
Multiply $789 \times 11$ by breaking it down as:
$789 \times 11 = 789 \times (10 + 1) = 7890 + 789 = 8679$
Alternatively, applying digit-wise addition for a 3-digit number:
$(7)\ (8 + 7)\ (9 + 8)\ (9) = (7)\ (15)\ (17)\ (9)$
Carry over the excess:
$7\ (15 + 1)\ (7 + 1)\ 9 = 7\ 16\ 8\ 9 = 8679$

Key Concept: Fast Multiplications Using the Distributive Property

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To find the product of 2468 × 11 using the distributive property:
Step 1: Multiply 2468 by 10: $2468 × 10 = 24680$
Step 2: Multiply 2468 by 1: $2468 × 1 = 2468$
Step 3: Add the partial results: $24680 + 2468 = 27148$
The assertion states that this can also be done by adding adjacent digits:
2 (thousands place), (2+4=6) (hundreds place), (4+6=10) (tens place), (6+8=14) (units place), and 8 (last digit). However, carrying over is needed here:
2 → 6 → (10 makes 0 with carryover 1 to next digit) → (14 + 1 = 15 makes 5 with carryover 1 to next digit) → (8 + 1 = 9).
Final result: 27148, which matches previous calculation. The reason correctly explains the method using distributive property.
Therefore, both Assertion and Reason are true, and Reason is the correct explanation of Assertion.

Key Concept: Fast Multiplication Using Distributive Property

c) 13574
[Solution Description]
To multiply $1234 \times 11$, we use the distributive property:
$1234 \times 11 = 1234 \times (10 + 1) = 12340 + 1234 = 13574$
Alternatively, using digit-wise addition:
$1\ (2+1)\ (3+2)\ (4+3)\ 4 = 1\ 3\ 5\ 7\ 4 = 13574$

Key Concept: Fast Multiplication Using Distributive Property

a) 5016
[Solution Description]
Apply the distributive property to $456 \times 11$:
$456 \times 11 = 456 \times (10 + 1) = 4560 + 456 = 5016$

Key Concept: Algebraic Pattern Investigation: Sum of Squares and Difference of Squares

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that for any two natural numbers $a$ and $b$, $2(a^2 + b^2)$ can be written as $(a + b)^2 + (a - b)^2$. This is supported by the algebraic identity provided in the reason. By expanding $(a + b)^2$ and $(a - b)^2$:
$(a + b)^2 = a^2 + 2ab + b^2 \\ \\ (a - b)^2 = a^2 - 2ab + b^2$
Adding these two equations gives:
$(a + b)^2 + (a - b)^2 = 2a^2 + 2b^2 = 2(a^2 + b^2)$
Thus, the assertion is true, and the reason correctly explains it using the derived identity.

Key Concept: Difference of squares

d) 64
[Solution Description]
To find $10^2 - 6^2$, use the identity $a^2 - b^2 = (a + b)(a - b)$.
Here, $a = 10$ and $b = 6$.
Substituting these values into the identity:
$10^2 - 6^2 = (10 + 6)(10 - 6)$
Calculate each part step-by-step:
$10 + 6 = 16$
$10 - 6 = 4$
Now multiply them:
$16 \times 4 = 64$

Key Concept: Algebraic Identities

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that the identity $(a + b)(a - b) = a^2 - b^2$ simplifies multiplication, which is true as shown in examples like $98 \times 102 = 100^2 - 2^2 = 9996$. The reason explains that this identity comes from the distributive property, which is also correct because expanding $(a + b)(a - b)$ gives $a^2 - ab + ab - b^2 = a^2 - b^2$, confirming the identity. Thus, the reason correctly explains the assertion.

Key Concept: Applying $(a + b

a) 95
[Solution Description]

We know that
$(a+b)(a-b)=a^2-b^2$

Here,
$a=12,\quad b=7$

So,
$(12+7)(12-7)=12^2-7^2$

$=144-49$

$=95$

Therefore, the value of
$(12+7)(12-7)$
is 95.

Key Concept: Square of binomial, Expanding expressions

c) $16x^2 + 56x + 49$
[Solution Description]
Applying the identity $(a + b)^2 = a^2 + 2ab + b^2$ with $a = 4x$ and $b = 7$, we get:
$(4x)^2 + 2(4x)(7) + 7^2 = 16x^2 + 56x + 49$

Key Concept: Using identities to simplify expressions

d) 64
[Solution Description]
To solve $(5 + 3)^2$, apply the identity $(a + b)^2 = a^2 + 2ab + b^2$.
Here, $a = 5$ and $b = 3$.
Substituting these values into the identity:
$(5 + 3)^2 = 5^2 + 2 \times 5 \times 3 + 3^2$
Calculate each term step-by-step:
$5^2 = 25$
$2 \times 5 \times 3 = 30$
$3^2 = 9$
Now add all terms:
$25 + 30 + 9 = 64$

Key Concept: Sum of squares, Algebraic identities

a) 100
[Solution Description]
Plugging in $a = 8$ and $b = 6$ into the identity:
$2(8^2 + 6^2) = (8 + 6)^2 + (8 - 6)^2$
$2(64 + 36) = 14^2 + 2^2$
$200 = 196 + 4$
Now, solving for $a^2 + b^2$:
$2(a^2 + b^2) = 200 \implies a^2 + b^2 = 100$

Key Concept: Using the identity $a^2 - b^2 = (a + b

b) 2200
[Solution Description]

We know that
$a^2 - b^2 = (a-b)(a+b)$

Here,
$a = 47,\quad b = 3$

So,
$47^2 - 3^2 = (47-3)(47+3)$

$= 44 \times 50$
$= 2200$

Therefore, the value of
$47^2 - 3^2$
is 2200.

Key Concept: Using the identity $(a + b

c) 25
[Solution Description]

We know that
$(a+b)^2 = a^2 + 2ab + b^2$

Here, $((x+5)^2)$ means $(a=x)$ and $(b=5).$ So,
$(x+5)^2 = x^2 + 2(x)(5) + 5^2$
$= x^2 + 10x + 25$

Comparing this with
$x^2 + 10x + k$

we get:
$k = 25$

So, the value of $k$ is $(\boxed{25}\).$

Key Concept: Verifying patterns

a) $100 + 16 = 116$
[Solution Description]
The given pattern is $(a + b)^2 + (a - b)^2 = 2(a^2 + b^2)$. Substitute $a = 7$ and $b = 3$ into the equation.
First calculate $(a + b)^2$:
$(7 + 3)^2 = 10^2 = 100$
Next calculate $(a - b)^2$:
$(7 - 3)^2 = 4^2 = 16$
Add the two results:
$100 + 16 = 116$
Now compute $2(a^2 + b^2)$:
$a^2 = 7^2 = 49$
$b^2 = 3^2 = 9$
Sum them:
$49 + 9 = 58$
Multiply by 2:
$2 \times 58 = 116$
Both sides are equal, confirming the pattern holds.

Key Concept: Using identities to explain numerical puzzles

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that $(10 + 5)^2$ can be expanded using the identity $(a + b)^2 = a^2 + 2ab + b^2$. This is correct because the identity holds for any real numbers $a$ and $b$, including 10 and 5. Applying it, we get:
$(10 + 5)^2 = 10^2 + 2 \times 10 \times 5 + 5^2 = 100 + 100 + 25 = 225$
The reason correctly explains why the identity works: the square of a binomial indeed equals the sum of the squares of the terms and twice their product. Therefore, both Assertion and Reason are true, and Reason is the correct explanation of Assertion.

Key Concept: Difference of squares, Algebraic identities

a) 4891
[Solution Description]
We can express $73 \times 67$ as $(70 + 3)(70 - 3)$. Using the difference of squares identity, this becomes:
$70^2 - 3^2 = 4900 - 9 = 4891$

Key Concept: Complex Expression Simplification

a) $2p^2 + 6pq + 6p - 2q$
[Solution Description]
Let's simplify step by step:
1. Expand first term: $2p(p+3q) = 2p^2 + 6pq$
2. Expand second term: $-3(q-2p) = -3q + 6p$
3. Now we have: $2p^2 + 6pq - 3q + 6p + q$
4. Combine like terms: $-3q + q = -2q$
5. Final form: $2p^2 + 6pq + 6p - 2q$

Key Concept: Expanding and Simplifying Algebraic Expressions

c) $15p^2 - 6pq$
[Solution Description] To expand and simplify $–3p (–5p + 2q)$, distribute $-3p$ to each term inside the parentheses:
$-3p \times (-5p) + (-3p) \times 2q = 15p^2 - 6pq$
The simplified form is $15p^2 - 6pq$.

Key Concept: Simplifying Polynomials

b) $5w^2 + 6w$
[Solution Description]
The expression $5w^2 + 6w$ cannot be simplified further because the terms $5w^2$ and $6w$ are not like terms (they have different exponents). Therefore, the correct answer is the expression itself.

Key Concept: Algebraic Expansion and Simplification

a) $12xy - 8xz + 10x - 5y$
[Solution Description]
First, expand each term separately:
1. $4x(3y - 2z) = 12xy - 8xz$
2. $5(2x - y) = 10x - 5y$
Now combine these results:
$12xy - 8xz + 10x - 5y$
There are no like terms to combine further, so this is the simplified form.

Key Concept: Binomial Squaring Error Identification

b) Omitted the middle term $-24ab$
[Solution Description]
The correct expansion using $(x - y)^2 = x^2 - 2xy + y^2$ would be:
$(3a - 4b)^2 = (3a)^2 - 2(3a)(4b) + (4b)^2 = 9a^2 - 24ab + 16b^2$
The student's error was:
1. They correctly squared both terms ($9a^2$ and $16b^2$)
2. But they forgot to include the middle term $-24ab$
3. They also used addition between the squared terms instead of subtraction

Key Concept: Distributive Property

d) Assertion is false, but Reason is true.
[Solution Description]
The given Assertion states that $(3x - 4)^2 = 9x^2 - 16$. However, using the correct identity $(a - b)^2 = a^2 - 2ab + b^2$, the expansion should be:
$(3x - 4)^2 = (3x)^2 - 2(3x)(4) + (4)^2 = 9x^2 - 24x + 16$.
The Reason correctly states the expansion formula for $(a - b)^2$, which is not applied in the Assertion.
Therefore, the Assertion is false, but the Reason is true.

Key Concept: Expanding Binomials

b) $ab + 4a + 2b + 8$
[Solution Description]
To expand $(a + 2)(b + 4)$, we use the distributive property (FOIL method):
$a \times b = ab, \quad a \times 4 = 4a, \quad 2 \times b = 2b, \quad 2 \times 4 = 8$
Combining these gives the expanded form $ab + 4a + 2b + 8$.

Key Concept: Algebraic Simplification

d) Assertion is false, but Reason is true.
[Solution Description]
Let us simplify the given expression step by step:
First, expand the expression:
$2(x - 1) + 3(x + 4) = 2x - 2 + 3x + 12$
Now, combine like terms:
$2x + 3x = 5x$ and $-2 + 12 = 10$
So, the correct simplified form is $5x + 10$, not $5x + 11$.
The Reason states that $-2$ and $+12$ were incorrectly combined as $+3$, which is false because they were actually correctly combined as $+10$.
Therefore, Assertion is false, but Reason is true.

Key Concept: Combining Like Terms

c) $5x + 10$
[Solution Description] First, distribute the coefficients:
$2(x - 1) = 2x - 2$
$3(x + 4) = 3x + 12$
Next, combine like terms:
$2x - 2 + 3x + 12 = (2x + 3x) + (-2 + 12) = 5x + 10$
The correct simplification is $5x + 10$.

Key Concept: Algebraic Simplification, Error Identification

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To verify, let's expand $(5m + 6n)^2$ using the identity $(a + b)^2 = a^2 + 2ab + b^2$. Here, $a = 5m$ and $b = 6n$. Substituting these values into the identity, we get:
$(5m + 6n)^2 = (5m)^2 + 2(5m)(6n) + (6n)^2 = 25m^2 + 60mn + 36n^2$
The given simplification in the problem statement only includes $25m^2 + 36n^2$, missing the middle term $60mn$. Therefore, both Assertion and Reason are true, and Reason correctly explains why the given simplification is incorrect.

Key Concept: Checking Errors in Expansion

a) Missing the term $60mn$
[Solution Description] The expression $(5m + 6n)^2$ should be expanded using the formula $(a+b)^2 = a^2 + 2ab + b^2$.
$(5m + 6n)^2 = (5m)^2 + 2 \times 5m \times 6n + (6n)^2 = 25m^2 + 60mn + 36n^2$
The given simplification misses the middle term $60mn$.

Key Concept: Expanding and Simplifying Algebraic Expressions

b) $–3p (–5p + 2q) = 15p^2 - 6pq$
[Solution Description]
The mistake is in the expansion. The correct expansion of $-3p(-5p + 2q)$ should use the distributive property:
$-3p \times (-5p) = 15p^2, \quad -3p \times 2q = -6pq$
So the correct simplified form is $15p^2 - 6pq$, not $p - 2q$.

Key Concept: Algebraic Pattern Investigation

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
First, evaluate the Assertion:
For $n = 10$, using the formula $n^2 + 2n$, we get $10^2 + 2 \times 10 = 100 + 20 = 120$. So, the Assertion is true.
Now, check the Reason:
Expand $(n+1)^2 - 1$:
$(n+1)^2 - 1 = n^2 + 2n + 1 - 1 = n^2 + 2n$. This matches the formula in the Assertion. Hence, the Reason is true and correctly explains the Assertion.

Key Concept: Difference of Squares Identity

c) 125
[Solution Description]
Apply the difference of squares identity:
$a^2 - b^2 = (a + b)(a - b)$.
Here, $a = 15$ and $b = 10$.
So, $15^2 - 10^2 = (15 + 10)(15 - 10) = 25 \times 5 = 125$.
Therefore, the value is 125.

Key Concept: Algebraic Pattern - Circles

c) 63
[Solution Description]
To find the number of circles in Step $k$, use the formula:
$k^2 + 2k$.
Substitute $k = 7$:
$7^2 + 2 \times 7 = 49 + 14 = 63$.
Therefore, there are 63 circles in Step 7.

Key Concept: Sum of Squares, Difference of Squares

b) 8
[Solution Description]
Using the identity $2(a^2 + b^2) = (a+b)^2 + (a-b)^2$ with $a=9$ and $b=4$:
$2(9^2 + 4^2) = (9+4)^2 + (9-4)^2 = 13^2 + 5^2 = 169 + 25 = 194$
The two squared terms obtained are $169$ and $25$.
Their square roots are $\sqrt{169} = 13$ and $\sqrt{25} = 5$.
The difference between these square roots is $13 - 5 = 8$.
Alternatively, note that $(a+b)-(a-b) = 2b = 8$ which matches our calculation.

Key Concept: Difference of Squares

c) $100^2 - 8^2$
[Solution Description]
To find $108 \times 92$ using the difference of squares identity $(a+b)(a-b)=a^2-b^2$, we need to express it in terms of $(a+b)(a-b)$.
Let's find $a$ and $b$ such that:
$a + b = 108$
$a - b = 92$
Adding these equations:
$2a = 200 \Rightarrow a = 100$
Subtracting them:
$2b = 16 \Rightarrow b = 8$
Now apply the identity:
$108 \times 92 = (100+8)(100-8) = 100^2 - 8^2 = 10000 - 64 = 9936$
We can also verify:
$108 \times 90 = 9720$
$108 \times 2 = 216$
Total $9720 + 216 = 9936$
Thus, the equivalent expression is $100^2 - 8^2$.

Key Concept: Sum of Squares, Difference of Squares

c) 361
[Solution Description]
First, identify $a$ and $b$ from the given expression $2(12^2 + 7^2)$. Here $a=12$ and $b=7$. Using the identity:
$2(a^2 + b^2) = (a+b)^2 + (a-b)^2$
Substitute the values:
$2(12^2 + 7^2) = (12+7)^2 + (12-7)^2$
Calculate each term:
$(12+7)^2 = 19^2 = 361$
$(12-7)^2 = 5^2 = 25$
Therefore, one of the terms in the sum is 361.

Key Concept: Algebraic Identities

b) 9996
[Solution Description]
Rewrite $98 \times 102$ as $(100 - 2)(100 + 2)$. Using the identity $a^2 - b^2 = (a + b)(a - b)$, we get:
$(100 - 2)(100 + 2) = 100^2 - 2^2 = 10000 - 4 = 9996$
So, $98 \times 102 = 9996$.

Key Concept: Sum of Squares Identity

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To verify the assertion, let us expand both $(a + b)^2$ and $(a - b)^2$ using the algebraic identities:
Step 1: Expand $(a + b)^2$:
$(a + b)^2 = a^2 + 2ab + b^2$
Step 2: Expand $(a - b)^2$:
$(a - b)^2 = a^2 - 2ab + b^2$
Step 3: Add the two expansions:
$(a + b)^2 + (a - b)^2 = (a^2 + 2ab + b^2) + (a^2 - 2ab + b^2)$
Step 4: Simplify the result:
$2a^2 + 2b^2 = 2(a^2 + b^2)$
Thus, the assertion is true because the equation holds for any natural numbers $a$ and $b$. The reason correctly explains how the identity is derived by adding the expansions of $(a + b)^2$ and $(a - b)^2$.

Key Concept: Algebraic Pattern Investigation

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To verify the assertion, let's expand both sides of the given equation using algebraic identities:
Right-hand side (RHS):
$(a + b)^2 + (a - b)^2 = (a^2 + 2ab + b^2) + (a^2 - 2ab + b^2) = 2a^2 + 2b^2$
Left-hand side (LHS):
$2(a^2 + b^2) = 2a^2 + 2b^2$
Since LHS = RHS, the assertion is true.
The reason provides the correct expansion formulas for $(a + b)^2$ and $(a - b)^2$, which are directly used to prove the assertion. Hence, the reason is the correct explanation of the assertion.

Key Concept: Increments in Products

c) $a + b + 1$
[Solution Description]
According to the given pattern, increasing both numbers $a$ and $b$ by 1 increases the product by $a + b + 1$. For example, with $a = 23$ and $b = 27$, the increment is $23 + 27 + 1 = 51$.

Key Concept: Pattern of Circles

c) 120
[Solution Description]
Substitute $k = 10$ into the expression $k^2 + 2k$:
$10^2 + 2 \times 10 = 100 + 20 = 120$
Thus, the number of circles in Step 10 is 120.

Key Concept: Algebraic Pattern - Square Tiles

c) 35
[Solution Description]
The formula for the number of tiles is $(n + 1)^2 - 1$.
Substitute $n = 5$:
$(5 + 1)^2 - 1 = 6^2 - 1 = 36 - 1 = 35$.
Therefore, there are 35 tiles in Step 5.

Key Concept: Sridharacharya's Method for Squares

c) 2704
[Solution Description]
Using the identity $(a^2 = (a + b)(a - b) + b^2)$, set $a = 52$ and $b = 2$:
$52^2 = (52 + 2)(52 - 2) + 2^2 = 54 \times 50 + 4 = 2700 + 4 = 2704$.

Key Concept: Pattern recognition in identities

b) $x^3 - y^3$
[Solution Description]
The given expression follows the pattern $(a - b)(a^2 + ab + b^2) = a^3 - b^3$.
Thus, $(x - y)(x^2 + xy + y^2) = x^3 - y^3$.

Key Concept: Quick multiplication using identities

c) 495
[Solution Description]
To find $45 \times 11$, use the distributive property:
$45 \times 11 = 45 \times (10 + 1) = 45 \times 10 + 45 \times 1 = 450 + 45 = 495$.

Key Concept: Pattern Recognition in Products

c) $x^2 - 9$
[Solution Description]
Using the difference of squares identity $(a - b)(a + b) = a^2 - b^2$, substitute $a = x$ and $b = 3$:
$(x - 3)(x + 3) = x^2 - 3^2 = x^2 - 9$.

Key Concept: Quick multiplication using identities, distributive property

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
Solution:
Step 1: Identify $a$ and $b$ in the given problem. Here, $197 = 200 - 3$ and $203 = 200 + 3$, so $a = 200$ and $b = 3$.
Step 2: Apply the identity $(a + b)(a - b) = a^2 - b^2$. Substituting $a = 200$ and $b = 3$, we get:
$(200 + 3)(200 - 3) = 200^2 - 3^2 = 40000 - 9 = 39991$
Step 3: Therefore, $197 \times 203 = 39991$.
The Assertion correctly identifies the application of the identity $(a + b)(a - b) = a^2 - b^2$, and the Reason provides the correct explanation for why this method works (i.e., the numbers are equidistant from $200$).

Key Concept: Quick multiplication using identities

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
Let us verify the assertion with an example:
Take a 3-digit number, say $123$. Multiplying it by $101$:
$123 \times 101 = 123 \times (100 + 1) = 12300 + 123 = 12423$
As seen, the result is obtained by writing the number $123$ twice ($123$ followed by $23$ for a 3-digit case).
The reason correctly explains the assertion using the distributive property $(a \times (100 + 1) = 100a + a)$. Hence, both Assertion and Reason are true, and Reason is the correct explanation of Assertion.

Key Concept: Sridharacharya's method for squares

c) 2401
[Solution Description]
Using the identity $(a + b)(a - b) + b^2 = a^2$, choose $b = 1$ for $a = 49$.
Therefore, $(49 + 1)(49 - 1) + 1^2 = 50 \times 48 + 1 = 2400 + 1 = 2401$.

Key Concept: Squaring numbers using identities

c) 27225
[Solution Description]
To compute $165^2$ using the given identity, let us choose $b = 5$:
Step 1: Apply the identity:
$165^2 = (165 + 5)(165 - 5) + 5^2$
Step 2: Compute $(165 + 5) = 170$ and $(165 - 5) = 160$
Step 3: Multiply them: $170 \times 160 = 27200$
Step 4: Add $5^2 = 25$: $27200 + 25 = 27225$
Therefore, $165^2 = 27225$.

Key Concept: Quick multiplication using identities

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To multiply a two-digit number $ab$ by 11, we use the distributive property:
$ab \times 11 = ab \times (10 + 1) = ab \times 10 + ab \times 1$.
This results in shifting the number left by one digit and adding the original number:
$ab0 + ab = a \quad (a + b) \quad b$.
For example, $42 \times 11 = 420 + 42 = 462$.
The Assertion is true, and the Reason correctly explains it.

Key Concept: Quick multiplication using identities

c) 88804
[Solution Description]
To find $298^2$ using Sridharacharya's identity $a^2 = (a + b)(a - b) + b^2$, we choose $b = 2$ since it makes $(a + b)$ and $(a - b)$ easy to multiply.
Step 1: Apply the identity:
$298^2 = (298 + 2)(298 - 2) + 2^2$
Step 2: Calculate $(298 + 2) = 300$ and $(298 - 2) = 296$
Step 3: Multiply them: $300 \times 296 = 88800$
Step 4: Add $2^2 = 4$ to the result: $88800 + 4 = 88804$
Therefore, $298^2 = 88804$.

Key Concept: Quick multiplication using identities

b) 627
[Solution Description]
Using the distributive property for multiplying by 11:
Break down $57 \times 11 = 57 \times (10 + 1) = 57 \times 10 + 57 \times 1 = 570 + 57 = 627$.

Key Concept: Multiplication with 11, 101, etc.

d) 732553
[Solution Description]
To multiply $7253 \times 101$, we use the identity for multiplying by 101 ($100 + 1$):
Step 1: Break down the multiplication:
$7253 \times 101 = 7253 \times (100 + 1) = 7253 \times 100 + 7253 \times 1$
Step 2: Compute $7253 \times 100 = 725300$
Step 3: Compute $7253 \times 1 = 7253$
Step 4: Add the results: $725300 + 7253 = 732553$
Therefore, $7253 \times 101 = 732553$.

Key Concept: Incremental Changes in Products

b) $a + b + 1$
[Solution Description]
When both numbers are increased by 1, the new product becomes $(a + 1)(b + 1) = ab + a + b + 1$. The increase in the product is $(ab + a + b + 1) - ab = a + b + 1$.

Key Concept: Distributive Property

b) 312
[Solution Description]
We can express $13 \times 24$ as $(12 + 1)(25 - 1)$. Using the formula $(a + m)(b + n) = ab + an + bm + mn$, where $a = 12$, $b = 25$, $m = 1$, and $n = -1$, we get:
$12 \times 25 + 12 \times (-1) + 25 \times 1 + 1 \times (-1) = 300 - 12 + 25 - 1 = 312$
Thus, $13 \times 24 = 312$.

Key Concept: Incremental Changes in Products, Distributive Property

c) $p + 99$
[Solution Description]
Using the property $(a + m)(b + n) = ab + an + bm + mn$, where $a = 12$, $b = 18$, and $m = n = 3$:
$(12 + 3)(18 + 3) = 12 \times 18 + 12 \times 3 + 18 \times 3 + 3 \times 3$
$= p + 36 + 54 + 9$
$= p + 99$.

Key Concept: Incremental Changes in Products, Mixed Operations

a) $P + xy + 15x + 9y + 5$
[Solution Description]
Let $x' = x + 1$ and $y' = y - 2$. The new product is:
$(5(x + 1) + 2(y - 2))(3(x + 1) - (y - 2))$
Simplify each part:
$= (5x + 5 + 2y - 4)(3x + 3 - y + 2)$
$= (5x + 2y + 1)(3x - y + 5)$.
Expand using the distributive property:
$= 5x \cdot 3x + 5x \cdot (-y) + 5x \cdot 5 + 2y \cdot 3x + 2y \cdot (-y) + 2y \cdot 5 + 1 \cdot 3x + 1 \cdot (-y) + 1 \cdot 5$
$= 15x^2 - 5xy + 25x + 6xy - 2y^2 + 10y + 3x - y + 5$
Combine like terms:
$= 15x^2 + xy + 28x - 2y^2 + 9y + 5$.
The original product $P = 15x^2 - xy + 13x - 2y^2$.
The difference is $(xy + 15x + 9y + 5)$.

Key Concept: Incremental Changes in Products

a) $a$
[Solution Description]
When the second number $b$ is increased by 1, the new product becomes $a(b + 1) = ab + a$. The increase in the product is $(ab + a) - ab = a$.

Key Concept: Incremental Changes in Products

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that increasing both numbers in a product by 1 results in an increase of $a + b + 1$ in the product. This is correct because:
1. Starting with two numbers $a$ and $b$, their product is $ab$.
2. After increasing both by 1, we get $(a+1)(b+1)$.
3. Expanding this using the distributive property:
$(a+1)(b+1) = ab + a + b + 1$.
4. The difference between the new product and the original product is $(ab + a + b + 1) - ab = a + b + 1$.
The reason correctly explains the assertion by showing the algebraic expansion that justifies the increase. Therefore, both the assertion and reason are true, and the reason is the correct explanation of the assertion.

Key Concept: Incremental Changes in Products

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
According to the distributive property, when one of the numbers in a product (e.g., $a$) is increased by 1, the new product becomes $(a + 1)b = ab + b$. This means the increase in the product is equal to the other number ($b$). The reason correctly explains the assertion using the distributive property of multiplication.

Key Concept: Incremental Changes in Products

d) Assertion is false, but Reason is true.
[Solution Description]
To verify the Assertion and Reason, let us analyze the expression $(a + 1)(b - 1)$. Expanding this gives:
$(a + 1)(b - 1) = ab - a + b - 1 = ab + (b - a - 1).$
The Assertion states that $(a + 1)(b - 1) < ab$ for all $a$ and $b$, which implies $(b - a - 1) ab$. The Reason is also false because $(b - a - 1)$ is not always negative. Therefore, the correct answer is (d).

Key Concept: Incremental Changes in Products

c) 30
[Solution Description]
The new product after increasing the first number by 3 and decreasing the second number by 2 is $(15 + 3)(22 - 2) = 18 \times 20 = 360$. The change in product is calculated as $360 - 330 = 30$.
Alternatively, using the formula for incremental changes:
$(a + m)(b + n) = ab + an + bm + mn$
Here, $a = 15$, $b = 22$, $m = 3$, and $n = -2$. Substituting these values, we get:
$15 \times (-2) + 22 \times 3 + 3 \times (-2) = -30 + 66 - 6 = 30$
Thus, the product increases by 30.

Key Concept: Incremental Changes in Products

c) 26
[Solution Description]
The original product is $8 \times 17 = 136$. After increasing both numbers by 1, the new product is $(8 + 1)(17 + 1) = 9 \times 18 = 162$. The change in product is $162 - 136 = 26$.
Using the formula $(a + 1)(b + 1) = ab + (a + b + 1)$, we substitute $a = 8$, $b = 17$, which gives:
$8 \times 17 + (8 + 17 + 1) = 136 + 26 = 162$
Therefore, the product increases by 26.

Key Concept: Incremental Changes in Products

b) $b$
[Solution Description]
When the first number $a$ is increased by 1, the new product becomes $(a + 1)b = ab + b$. The increase in the product is $(ab + b) - ab = b$.

Key Concept: Fast Multiplication, Distributive Property

b) $249268$
[Solution Description]
Rewrite 101 as $(100 + 1)$ and apply the distributive property:
$2468 \times 101 = 2468 \times (100 + 1)$
$= 2468 \times 100 + 2468 \times 1$
$= 246800 + 2468$
$= 249268$.

Key Concept: Square of the Sum of Two Numbers

c) $x^2 + 8x + 16$
[Solution Description]
Using the identity $(a + b)^2 = a^2 + 2ab + b^2$, substitute $a = x$ and $b = 4$.
Step 1: Square the first term: $x^2$.
Step 2: Multiply the two terms and double the result: $2 \times (x \times 4) = 8x$.
Step 3: Square the second term: $4^2 = 16$.
Final expansion: $x^2 + 8x + 16$.

Key Concept: Square of the Sum of Two Numbers

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To solve this, use the identity for the square of the sum of two numbers: $(a + b)^2 = a^2 + 2ab + b^2$. Here, $a = 3$ and $b = 4$.
Step 1: Calculate $a^2$ which is $3^2 = 9$.
Step 2: Calculate $2ab$ which is $2 \times 3 \times 4 = 24$.
Step 3: Calculate $b^2$ which is $4^2 = 16$.
Adding these together gives $9 + 24 + 16 = 49$, which matches $(3 + 4)^2 = 7^2 = 49$.
Therefore, both the Assertion and Reason are true, and the Reason correctly explains the Assertion.

Key Concept: Square of the Difference of Two Numbers

b) $25 - 10y + y^2$
[Solution Description]
Using the identity $(a - b)^2 = a^2 - 2ab + b^2$, substitute $a = 5$ and $b = y$.
Step 1: Square the first term: $5^2 = 25$.
Step 2: Multiply the two terms and double the result: $-2 \times (5 \times y) = -10y$.
Step 3: Square the second term: $y^2$.
Final expansion: $25 - 10y + y^2$.

Key Concept: Square of the Difference, Pattern Recognition

c) 9801
[Solution Description]
Using the identity $(a - b)^2 = a^2 - 2ab + b^2$ where $a = 100$ and $b = 1$:
$(100 - 1)^2 = 100^2 - 2 \times 100 \times 1 + 1^2$
$= 10000 - 200 + 1$
$= 9801$.

Key Concept: Square of the Difference of Two Numbers

c) $25y^2 - 20y + 4$
[Solution Description]
The identity $(a - b)^2 = a^2 - 2ab + b^2$ is used here with $a = 5y$ and $b = 2$. Substituting:
$(5y - 2)^2 = (5y)^2 - 2(5y)(2) + 2^2 = 25y^2 - 20y + 4$.

Key Concept: Square of the Sum of Two Numbers

c) $9x^2 + 24x + 16$
[Solution Description]
We use the identity $(a + b)^2 = a^2 + 2ab + b^2$. Here, $a = 3x$ and $b = 4$. Substituting these values into the identity:
$(3x + 4)^2 = (3x)^2 + 2(3x)(4) + 4^2 = 9x^2 + 24x + 16$.

Key Concept: Difference of Squares, Multi-step Solution

c) 9996
[Solution Description]
We use the identity $(a + b)(a - b) = a^2 - b^2$ with $a = 100$ and $b = 2$:
$(100 - 2)(100 + 2) = 100^2 - 2^2$
$= 10{,}000 - 4$
$= 9996$.

Key Concept: Application of Identity 1A

c) 121
[Solution Description]
Using the identity $(a + b)^2 = a^2 + 2ab + b^2$, substitute $a = 10$ and $b = 1$.
Step 1: Square the first term: $10^2 = 100$.
Step 2: Multiply the two terms and double the result: $2 \times (10 \times 1) = 20$.
Step 3: Square the second term: $1^2 = 1$.
Final calculation: $100 + 20 + 1 = 121$.

Key Concept: Application of Square of Sum/Difference

c) $42km$
[Solution Description]
Expanding $(7k + 3m)^2$ using the identity $(a + b)^2 = a^2 + 2ab + b^2$, where $a = 7k$ and $b = 3m$:
$(7k + 3m)^2 = (7k)^2 + 2(7k)(3m) + (3m)^2 = 49k^2 + 42km + 9m^2$. The middle term is $42km$.

Key Concept: Square of the Sum, Difference of Squares

c) 10816
[Solution Description]
We use the identity $(a + b)^2 = a^2 + 2ab + b^2$. Here, $a = 100$ and $b = 4$. Substituting these values:
$(100 + 4)^2 = 100^2 + 2 \times 100 \times 4 + 4^2$
$= 10000 + 800 + 16$
$= 10816$.

Key Concept: Square of the Difference of Two Numbers

d) Assertion is false, but Reason is true.
[Solution Description]
To verify the Assertion, we apply Identity 1B: $(a - b)^2 = a^2 - 2ab + b^2$. Here, $a = 3x$ and $b = 4y$. Substituting these values into the identity, we get $(3x - 4y)^2 = (3x)^2 - 2 \times 3x \times 4y + (4y)^2 = 9x^2 - 24xy + 16y^2$. However, the Assertion states the result as $9x^2 - 12xy + 16y^2$, which is incorrect because the middle term should be $-24xy$ instead of $-12xy$. The Reason correctly states the identity for the square of the difference of two numbers. Therefore, the Assertion is false, but the Reason is true.

Key Concept: Square of Sum/Difference, Distributive Property

d) Assertion is false, but Reason is true.
[Solution Description]
The assertion claims that $(a + b)^2$ is always greater than $a^2 + b^2$. The reason given is that the term $2ab$ ensures this inequality holds for non-zero $a$ and $b$.
Step 1: Expand $(a + b)^2$ using Identity 1A:
$(a + b)^2 = a^2 + 2ab + b^2$
Step 2: Compare $(a + b)^2$ with $a^2 + b^2$. The difference is $2ab$.
Step 3: The term $2ab$ can be positive, negative, or zero depending on the signs of $a$ and $b$:
- If $a$ and $b$ are both positive or both negative, $2ab > 0$, so $(a + b)^2 > a^2 + b^2$.
- If one of them is positive and the other is negative, $2ab < 0$, which may make $(a + b)^2 < a^2 + b^2$ (e.g., $a = 1$, $b = -1$ gives $(1 - 1)^2 = 0 < 1 + 1 = 2$). - If either $a$ or $b$ is zero, $2ab = 0$, making $(a + b)^2 = a^2 + b^2$. Thus, the assertion is false because $(a + b)^2$ is not always greater than $a^2 + b^2$. The reason is true when $a$ and $b$ are both non-zero and have the same sign, but it fails to account for cases where $2ab \leq 0$. Therefore, the reason does not fully explain the assertion, but it is conditionally correct.

Key Concept: Distributive Property, Algebraic Identities

b) $16k$
[Solution Description]
First, expand both squares using the identity $(a + b)^2 = a^2 + 2ab + b^2$ and $(a - b)^2 = a^2 - 2ab + b^2$.
$(k + 4)^2 = k^2 + 8k + 16$
$(k - 4)^2 = k^2 - 8k + 16$
Subtract the second expansion from the first:
$(k^2 + 8k + 16) - (k^2 - 8k + 16) = 16k$.
The simplified form is $16k$.

Key Concept: Distributive Property

b) 91
[Solution Description]
We can rewrite $13 \times 7$ as $(10 + 3)(10 - 3)$. Using the identity $(a + b)(a - b) = a^2 - b^2$, we get:
$(10 + 3)(10 - 3) = 10^2 - 3^2 = 100 - 9 = 91$
Thus, $13 \times 7 = 91$.

Key Concept: Pattern Recognition

c) 130
[Solution Description]
Using the given pattern, we substitute $a = 7$ and $b = 4$ into the identity:
$2(a^2 + b^2) = (a + b)^2 + (a - b)^2$
So,
$2(7^2 + 4^2) = (7 + 4)^2 + (7 - 4)^2 = 11^2 + 3^2 = 121 + 9 = 130$
Thus, $2(4^2 + 7^2) = 130$.

Key Concept: Pattern Recognition - Sum of Squares

c) 50
[Solution Description]
Substitute $a = 3$ and $b = 4$ into the formula: $(3 + 4)^2 + (3 - 4)^2 = 49 + 1 = 50$

Key Concept: Special Case Expansion

b) $k^2 + 2k$
[Solution Description]
The expression $k(k + 2)$ can be expanded using the distributive property:
$k(k + 2) = k \cdot k + k \cdot 2 = k^2 + 2k$
Therefore, $k(k + 2) = k^2 + 2k$.

Key Concept: Distributive Property, Multi-step Simplification

b) $116$
[Solution Description]
Substitute $a = 7$ and $b = 3$ into the given identity:
$2(7^2 + 3^2) = (7 + 3)^2 + (7 - 3)^2$
Calculate each part step-by-step:
$7^2 = 49$, $3^2 = 9$, so $2(49 + 9) = 2(58) = 116$.
$(7 + 3)^2 = 10^2 = 100$.
$(7 - 3)^2 = 4^2 = 16$.
Verify: $100 + 16 = 116$.
The value is $116$.

Key Concept: Distributive Property and Algebraic Identities

b) Both Assertion and Reason are true, but Reason is NOT the correct explanation of Assertion.
[Solution Description]
First, expand $(a + b)^2$ using the identity $(a + b)^2 = a^2 + 2ab + b^2$. Similarly, expand $(a - b)^2$ using $(a - b)^2 = a^2 - 2ab + b^2$. Now, subtract $(a - b)^2$ from $(a + b)^2$: $(a^2 + 2ab + b^2) - (a^2 - 2ab + b^2)$. Simplify by combining like terms: $a^2 - a^2 + 2ab + 2ab + b^2 - b^2 = 4ab$. Thus, Assertion is true. Reason uses the identity $(a + b)(a - b) = a^2 - b^2$, which is not directly applicable here since we used expansion of squares, not difference of squares. Hence, Reason is true but does not correctly explain the Assertion.

Key Concept: Distributive Property - Basic Application

b) 35
[Solution Description]
Substitute $k = 5$ into the formula $k^2 + 2k$. The calculation is: $5^2 + 2 \times 5 = 25 + 10 = 35$

Key Concept: Distributive Property

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To verify the assertion, we expand $(k + 1)^2 - 1$ step by step:
Step 1: Apply the identity $(a + b)^2 = a^2 + 2ab + b^2$.
So, $(k + 1)^2 = k^2 + 2 \times k \times 1 + 1^2 = k^2 + 2k + 1$.
Step 2: Subtract 1 from the expanded form.
Therefore, $(k + 1)^2 - 1 = k^2 + 2k + 1 - 1 = k^2 + 2k$.
This matches the given expression $k^2 + 2k$. Hence, both Assertion and Reason are true, and the Reason correctly explains the Assertion.

Key Concept: Sum of Squares, Difference of Squares

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
Let us verify the assertion by expanding both sides:
\textbf{Left Side:}
$2(a^2 + b^2) = 2a^2 + 2b^2$
\textbf{Right Side:}
$(a + b)^2 + (a - b)^2 = (a^2 + 2ab + b^2) + (a^2 - 2ab + b^2) = 2a^2 + 2b^2$
Both sides simplify to $2a^2 + 2b^2$, confirming the assertion is true. The reason provides the correct derivation steps, proving it is not only true but also the correct explanation.

Key Concept: Algebraic Identity - Difference of Squares

c) 9996
[Solution Description]
Express $98 \times 102$ as $(100 - 2)(100 + 2)$. Apply the difference of squares identity: $100^2 - 2^2 = 10000 - 4 = 9996$

Key Concept: Distributive Property, Pattern Recognition

b) $9951$
[Solution Description]
Express $107 \times 93$ as $(100 + 7)(100 - 7)$.
Using the identity $(a + b)(a - b) = a^2 - b^2$, substitute $a = 100$ and $b = 7$:
$(100 + 7)(100 - 7) = 100^2 - 7^2 = 10000 - 49 = 9951$.
The result is $9951$.

Key Concept: Pattern Interpretation

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that the expression $k^2 + 2k$ correctly gives the number of circles in Step k of the pattern, which is confirmed by the syllabus material. The Reason states that all four methods lead to this same expression, which is also true as shown in the syllabus. Furthermore, the Reason correctly explains why the Assertion is valid since it demonstrates multiple approaches converging to the same result.

Key Concept: Multiple Methods to Solve a Problem

c) 35
[Solution Description]
The first method gives $5 \times (5 + 2) = 5 \times 7 = 35$. According to the problem statement, all correct methods must yield the same result, so the other method must also give 35.

Key Concept: Pattern Recognition

c) 15
[Solution Description]
To find the number of circles in Step 3, substitute $k = 3$ into the given expression:
$k^2 + 2k = 3^2 + 2 \times 3 = 9 + 6 = 15$
So, there are 15 circles in Step 3.

Key Concept: Pattern Analysis

b) 35
[Solution Description]
To find the number of circles in Step 5, substitute $k = 5$ into the formula $k^2 + 2k$.
$5^2 + 2 \times 5 = 25 + 10 = 35$
Therefore, there are 35 circles in Step 5.

Key Concept: Pattern and Algebraic Expression

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that the expression $k^2 + 2k$ correctly gives the number of circles at any step $k$ in the pattern. This is true as verified by all four methods (Method 1: $(k + 1)^2 - 1$, Method 2: $k^2 + 2 \times k$, Method 3: $k \times (k + 1) + k$, and Method 4: $k \times (k + 2)$), which simplify to $k^2 + 2k$. Thus, the assertion is true.
The reason states that all four methods lead to the same simplified form $k^2 + 2k$. This is also true, as shown in the syllabus. Moreover, the reason correctly explains why the assertion is true because the equivalence of all methods confirms the validity of the expression $k^2 + 2k$ for the pattern.
Therefore, both the assertion and reason are true, and the reason is the correct explanation of the assertion.

Key Concept: Simplification

b) $k^2 + 2k$
[Solution Description]
Simplify the given expression step-by-step:
$(k + 1)^2 - 1 = k^2 + 2k + 1 - 1 = k^2 + 2k$
The simplified form is $k^2 + 2k$.

Key Concept: Pattern Prediction

b) 7
[Solution Description]
Given $k^2 + 2k = 63$, we solve for $k$:
$k^2 + 2k - 63 = 0$
$(k + 9)(k - 7) = 0$
Solutions are $k = -9$ (invalid since step cannot be negative) and $k = 7$.
Therefore, $n = 7$.

Key Concept: Expression Verification

a) $(k + 1)^2 - 1$
[Solution Description]
We need to verify which expression simplifies to $k^2 + 2k$:
\begin{itemize}

Key Concept: Pattern Generalization, Algebraic Expression

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To verify the assertion, let us simplify all four methods:
\textbf{Method 1}: $k \times (k + 2) = k^2 + 2k$
\textbf{Method 2}: $k \times (k + 1) + k = k^2 + k + k = k^2 + 2k$
\textbf{Method 3}: $k^2 + 2 \times k = k^2 + 2k$
\textbf{Method 4}: $(k + 1)^2 - 1 = k^2 + 2k + 1 - 1 = k^2 + 2k$
All four methods simplify to the same expression $k^2 + 2k$, confirming that the assertion is true. The reason correctly explains why the assertion holds, as it demonstrates that multiple valid methods converge to the same result.

Key Concept: Expression Evaluation

b) $(k + 1)^2 - 1$
[Solution Description]
The given formula is $k^2 + 2k$. Let's verify each option:
- Option 1: $k(k + 3) = k^2 + 3k$ → Not equivalent.
- Option 2: $(k + 1)^2 - 1 = k^2 + 2k + 1 - 1 = k^2 + 2k$ → Equivalent.
- Option 3: $k^2 + k + 2$ → Not equivalent.
- Option 4: $2k^2 + k$ → Not equivalent.
Hence, $(k + 1)^2 - 1$ is the correct equivalent expression.

Key Concept: Application

c) 24
[Solution Description]
Substitute $n = 4$ into the expression:
$n^2 + 2n = 4^2 + 2 \times 4 = 16 + 8 = 24$
There are 24 circles in Step 4.

Key Concept: Pattern Interpretation and Algebraic Expression

b) 440
[Solution Description]
To find the number of circles in Step 20, substitute $k = 20$ into the given formula:
$\text{Number of circles} = k^2 + 2k = 20^2 + 2 \times 20 = 400 + 40 = 440$

Key Concept: Distributive Property

b) Both Assertion and Reason are true, but Reason is NOT the correct explanation of Assertion.
[Solution Description]
To expand $(2x + 3)(4y - 5)$, we use the distributive property (also known as FOIL method for binomials). Multiply each term in the first bracket by each term in the second bracket:
$(2x)(4y) + (2x)(-5) + (3)(4y) + (3)(-5) = 8xy - 10x + 12y - 15$
The assertion is correct. The reason correctly states the distributive property, but it does not explicitly explain the expansion of two binomials (which requires applying the distributive property twice). Thus, while both are true, the reason does not fully explain the assertion.

Key Concept: Distributive Property, Fast Multiplication

a) 24543
[Solution Description]
We can express 101 as $(100 + 1)$. Using the distributive property:
$243 \times 101 = 243 \times (100 + 1) = (243 \times 100) + (243 \times 1) = 24300 + 243 = 24543$

Key Concept: Distributive Property

c) $15 + 40$
[Solution Description]
Using the distributive property, $a(b + c) = ab + ac$. Here, $a = 5$, $b = 3$, and $c = 8$. Therefore, $5(3 + 8) = (5 \times 3) + (5 \times 8) = 15 + 40 = 55$.

Key Concept: Special Case: Square of Sum

b) $49$
[Solution Description]
Applying the identity $(a + b)^2 = a^2 + 2ab + b^2$ where $a = 5$ and $b = 2$:
$(5 + 2)^2 = 5^2 + 2 \times 5 \times 2 + 2^2$
Calculating each term:
$25 + 20 + 4 = 49$
Thus, the value is $49$.

Key Concept: Distributive Property, Special Cases

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To expand $(x + y)^2$, we use the distributive property as follows:
$(x + y)^2 = (x + y)(x + y) = x \times x + x \times y + y \times x + y \times y = x^2 + 2xy + y^2$
Here, the assertion is true because $(x + y)^2$ indeed expands to $x^2 + 2xy + y^2$. The reason is also true and correctly explains the assertion, as the distributive property is used to break down the expression and perform the expansion.

Key Concept: Distributive Property Application

b) $12 + 3x + 4y + xy$
[Solution Description]
To expand $(4 + x)(3 + y)$, we use the distributive property:
$(4 + x)(3 + y) = 4 \times 3 + 4 \times y + x \times 3 + x \times y$
Simplifying each term gives:
$12 + 4y + 3x + xy$
So, the expanded form is $12 + 3x + 4y + xy$.

Key Concept: Fast Multiplication

b) $2323$
[Solution Description]
We can write $23 \times 101$ as $23 \times (100 + 1)$. Using the distributive property:
$23 \times 101 = 23 \times 100 + 23 \times 1$
Calculating each term:
$2300 + 23 = 2323$
Hence, the product is $2323$.

Key Concept: Square of Sum Identity

d) $16 + 40 + 25$
[Solution Description]
Applying the identity, $(a + b)^2 = a^2 + 2ab + b^2$. Substituting $a = 4$ and $b = 5$, we get $(4 + 5)^2 = 4^2 + 2 \times 4 \times 5 + 5^2 = 16 + 40 + 25 = 81$.

Key Concept: Distributive Property, Square of Sum

a) $25x^2 + 70xy + 49y^2$
[Solution Description]
To solve this, we use the square of sum formula: $(a + b)^2 = a^2 + 2ab + b^2$. Here, $a = 5x$ and $b = 7y$. Applying the formula:
$(5x)^2 + 2(5x)(7y) + (7y)^2 = 25x^2 + 70xy + 49y^2$

Key Concept: Distributive Property

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion is true because applying the distributive property to $5(3 + 4)$ indeed gives $5 \times 3 + 5 \times 4 = 15 + 20 = 35$. The reason correctly explains the distributive property, which is $a(b + c) = ab + ac$, and justifies the assertion.

Key Concept: Distributive Property, Product of Sum and Difference

a) $16a^2 - 81b^2$
[Solution Description]
This uses the product of sum and difference identity: $(a + b)(a - b) = a^2 - b^2$. Here, $a = 4a$ and $b = 9b$.
$(4a)^2 - (9b)^2 = 16a^2 - 81b^2$

Key Concept: Multiplication by Parts

b) $1212$
[Solution Description]
We can write $101$ as $(100 + 1)$. Thus, $12 \times 101 = 12 \times (100 + 1) = (12 \times 100) + (12 \times 1) = 1200 + 12 = 1212$.

Key Concept: Multiple methods

d) Method 4: $(k + 2)^2 - 4$
[Solution Description]
Let's verify each method:
1. Method 1: $k \times (k + 2) = k^2 + 2k$ — correct.
2. Method 2: $(k + 1)^2 - 1 = k^2 + 2k + 1 - 1 = k^2 + 2k$ — correct.
3. Method 3: $k \times (k + 1) + k = k^2 + k + k = k^2 + 2k$ — correct.
4. Method 4: $(k + 2)^2 - 4 = k^2 + 4k + 4 - 4 = k^2 + 4k$ — incorrect as it gives $k^2 +4k$ instead of $k^2 +2k$.
Thus, Method 4 is incorrect.

Key Concept: Pattern recognition, algebraic simplification

b) $k^2 + 5k + 8$
[Solution Description]
First, expand $(k + 3)^2$ using the formula $(a + b)^2 = a^2 + 2ab + b^2$. This gives $k^2 + 6k + 9$. Next, subtract $(k + 1)$ from this result: $k^2 + 6k + 9 - k - 1 = k^2 + 5k + 8$. Therefore, the simplified form is $k^2 + 5k + 8$.

Key Concept: Pattern Formula Verification

c) $k^2 + 2k$
[Solution Description]
Expand the given expression:
$k \times (k + 2) = k^2 + 2k$
Now compare it with other expressions. The option that matches $k^2 + 2k$ is correct.

Key Concept: Consistency of expressions

a) $(k+1)^2 -1$
[Solution Description]
To find an expression equal to $k^2 + 2k$, let's simplify each option:
1. Expanding $(k+1)^2 -1$ gives $k^2 + 2k + 1 -1 = k^2 + 2k$. This matches.
2. Simplifying $k(k + 1) + k$ gives $k^2 + k + k = k^2 + 2k$. This matches.
3. Factorizing $k(k + 2)$ directly gives $k^2 + 2k$. This matches.
4. The expression $(k + 2)^2 -4$ simplifies to $k^2 + 4k +4 -4 = k^2 +4k$ which doesn't match.
Therefore, options a), b), and c) are equivalent to $k^2 + 2k$.

Key Concept: Pattern Formula Application

b) 255
[Solution Description]
To find the number of circles at Step 15, substitute $k = 15$ into the formula:
$15^2 + 2 \times 15 = 225 + 30 = 255$
Therefore, the number of circles is 255.

Key Concept: Multiple methods for pattern representation, algebraic equivalence

c) Yes, they simplify to $k^2 + 4k$
[Solution Description]
First, simplify each expression:
1) $(k + 2)^2 - 4 = k^2 + 4k + 4 - 4 = k^2 + 4k$.
2) $k(k + 4) = k^2 + 4k$.
3) $4k + k^2 = k^2 + 4k$ (rearranged).
All three expressions simplify to $k^2 + 4k$, confirming their equivalence.

Key Concept: Consistency of expressions across different methods

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
First, let's evaluate Assertion (A): The expression provided is $k \times (k + 2)$, which simplifies to $k^2 + 2k$. This matches the general form given in the syllabus for the number of circles at Step k.
Next, let's evaluate Reason (R): The simplified form of $k \times (k + 2)$ indeed gives $k^2 + 2k$, and the syllabus confirms that this matches other alternative forms like $(k + 1)^2 - 1$ or $k \times (k + 1) + k$ when simplified further.
Since both Assertion and Reason are true, and Reason correctly explains why Assertion holds, the correct answer is option a).

Key Concept: Pattern analysis

c) 48
[Solution Description]
Given the formula for the number of circles at Step k is $k^2 + 2k$. For Step 6, substitute $k=6$ into the formula:
$6^2 + 2 \times 6 = 36 + 12 = 48$ circles.

Key Concept: Real-world application of patterns, step calculation

c) 70
[Solution Description]
Substitute $n = 7$ into the expression $n(n + 3)$: $7 \times (7 + 3) = 7 \times 10 = 70$. Thus, 70 tiles are needed for Step 7.

Key Concept: Consistency of expressions, Algebraic identities

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
To verify the assertion, let's simplify both expressions:
1. For $k \times (k + 2)$, we can expand it as follows:
$k \times (k + 2) = k^2 + 2k$
2. For $(k + 1)^2 - 1$, we use the formula $(a + b)^2 = a^2 + 2ab + b^2$:
$(k + 1)^2 - 1 = (k^2 + 2k + 1) - 1 = k^2 + 2k$
Both expressions simplify to $k^2 + 2k$, confirming they are equivalent for all integer values of $k$. Therefore, Assertion is true.
The Reason states that both expressions simplify to the same form $k^2 + 2k$, which is also true and correctly explains the Assertion.

Key Concept: Expression Simplification

b) $k^2 + 2k$
[Solution Description]
Expand and simplify the expression:
$(k + 1)^2 - 1 = k^2 + 2k + 1 - 1 = k^2 + 2k$
The simplified form is $k^2 + 2k$.

Key Concept: Consistency of expressions across different methods

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description] The assertion is true because when we simplify both expressions:
$k \times (k + 2) = k^2 + 2k$
$(k + 1)^2 - 1 = k^2 + 2k + 1 - 1 = k^2 + 2k$
Both expressions simplify to the same form, which proves their consistency. The reason is also true and correctly explains the assertion, as different algebraic methods indeed lead to the same simplified result.