Key Concept: Liquid Pressure, Pipe Diameter

c) The pressures are equal
[Solution Description]
Liquid pressure depends only on the height of the liquid column and its density, not on the cross-sectional area or shape of the container. Since both pipes are filled to the same height with water, the pressure at the bottom of both pipes is the same: $P = \rho g h$, where $\rho$ is density, $g$ is gravity, and $h$ is height.

Key Concept: Pressure, Force, Area

d) The pressure increases fivefold
[Solution Description]
The pressure exerted by an object is given by $Pressure = \frac{Force}{Area}$. Initially, the area in contact with the table is 2 m × 1 m = 2 $m^2$. So, the initial pressure is $\frac{100 N}{2 m^2} = 50 Pa$. When the block is rotated to stand on its shortest side (1 m), the new contact area becomes 2 m × 0.1 m = 0.2 $m^2$ (assuming thickness is 0.1 m). The new pressure is $\frac{100 N}{0.2 m^2} = 500 Pa$. Thus, the pressure increases.

Key Concept: Wind pressure conceptual complexity

a) 100 Pa
[Solution Description]
Original pressure:
$P_{original} = \frac{800}{8} = 100 \text{ Pa}$
New billboard area = 4 m$^2$. If force scales with area, new force:
$F_{new} = 100 \times 4 = 400 \text{ N}$
Pressure on new billboard remains the same because:
$P_{new} = \frac{400}{4} = 100 \text{ Pa}$
Thus, the pressure tolerance required is unchanged.

Key Concept: Pressure Comparison

a) Box A
[Solution Description]
Pressure is inversely proportional to area when force is constant. Since $P = \frac{F}{A}$, Box A with smaller area \(2\,\mathrm{m}^2\) will exert greater pressure than Box B \(4\ \mathrm{m}^2\).
Conclusion: Box A exerts more pressure.

Key Concept: Pressure Definition

c) Force applied per unit area
[Solution Description]
Pressure is defined as force per unit area. The formula is: $Pressure = \frac{Force}{Area}$.

Key Concept: Pressure and its SI unit

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that the SI unit of pressure is pascal (Pa), which is correct as per the syllabus. The reason explains that pressure is defined as force per unit area, with SI units of newton (N) for force and metre$^2$ ($m^2$) for area. This is also correct, and it correctly justifies why the unit of pressure is Pa, since $1\,Pa = 1\,N/m^2$. Therefore, both the assertion and reason are true, and the reason correctly explains the assertion.

Key Concept: Pressure, Force, Area

c) It increases by a factor of 5
[Solution Description]
Initial area of contact = $10 \text{ cm} \times 5 \text{ cm} = 50 \text{ cm}^2$.
Pressure initially = $\frac{\text{Force}}{\text{Area}} = \frac{50 \text{ N}}{50 \text{ cm}^2} = 1 \text{ N/cm}^2$.
When turned to smallest face, new area = $5 \text{ cm} \times 2 \text{ cm} = 10 \text{ cm}^2$ (assuming thickness is 2 cm).
New pressure = $\frac{50 \text{ N}}{10 \text{ cm}^2} = 5 \text{ N/cm}^2$.
Therefore, the pressure increases by a factor of 5.

Key Concept: Pressure and Area Relationship

c) Assertion is true, but Reason is false.
[Solution Description]
The assertion is correct because a sharp knife has a smaller area of contact compared to a blunt one for the same force, which leads to higher pressure according to $P = \frac{F}{A}$. However, the reason is incorrect because pressure is inversely proportional to the area of contact for a given force, not directly proportional. Therefore, the assertion is true, but the reason is false.

Key Concept: Pressure Applications

d) The pressure decreases
[Solution Description]
If the strap width is doubled, the area of contact increases. Since pressure is inversely proportional to area ($Pressure = \frac{Force}{Area}$), increasing the area reduces the pressure for the same applied force (weight of the bag). Therefore, the pressure exerted on the shoulder decreases.

Key Concept: Pressure, Area Relationship

b) Pressure doubles
[Solution Description]
The pressure is given by $P = \frac{F}{A}$. When the strap width is halved (from 5 cm to 2.5 cm), the area of contact decreases since $A$ is proportional to width for a given length. Thus, pressure doubles because $P$ is inversely proportional to $A$.

Key Concept: Pressure Directionality, Balloon Inflation

c) Air pressure acts equally in all directions.
[Solution Description]
Air inside the balloon exerts pressure uniformly in all directions. This is because gas molecules move randomly and collide with the inner walls of the balloon in every direction equally. As a result, the balloon expands symmetrically, demonstrating that air pressure is isotropic—it acts equally in all directions.

Key Concept: Sucker Experiment, Pressure Difference

c) External atmospheric pressure exceeds internal pressure of the sucker.
[Solution Description]
Pressing the sucker expels most of the air trapped between its cup and the surface. This reduces the internal air pressure, creating a pressure difference: the external atmospheric pressure is now higher than the pressure inside the sucker. The higher external pressure pushes the sucker against the surface, making it difficult to pull off. Only a strong enough force can overcome this pressure difference.

Key Concept: Magnitude of Atmospheric Pressure

c) The pressure inside our body balances the atmospheric pressure
[Solution Description]
Atmospheric pressure exerts a large force, but our body’s internal pressure balances it, preventing us from being crushed. This equilibrium ensures no net force acts on our bodies.

Key Concept: Atmospheric Pressure, Pressure-Force Relationship

b) Both Assertion and Reason are true, but Reason is NOT the correct explanation of Assertion.
[Solution Description]
The Assertion states that atmospheric pressure exerts a force of 2250 N over an area of 225 cm$^2$. From the given information, we know that the force exerted by the atmospheric air column over an area of 15 cm $\times$ 15 cm (225 cm$^2$) is nearly equal to 2250 N, which matches the Assertion. The Reason explains that the internal pressure in our bodies balances the external atmospheric pressure, preventing us from being crushed, which is also correct. However, the Reason does not explain why the Assertion is true (i.e., it does not justify the force calculation). Thus, both are true, but the Reason is not the correct explanation of the Assertion.

Key Concept: Atmospheric Pressure and Area

c) The force doubles because force is directly proportional to area under constant pressure.
[Solution Description]
Atmospheric pressure is defined as force per unit area ($P = F/A$). If the area ($A$) doubles while pressure ($P$) remains constant (since it's atmospheric pressure), the force ($F$) must also double to maintain the equation $F = P \times A$. Thus, the force increases with increased area.

Key Concept: Atmospheric Pressure

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that atmospheric pressure is the force exerted by air on all objects, which is correct as discussed in the syllabus. The Reason explains that air exerts pressure because it has mass and occupies space, which is also true and correctly explains the Assertion since the weight of air molecules creates pressure.

Key Concept: Air pressure, Surface area comparison

c) 1:4
[Solution Description]
1) When the chart paper is folded twice, its area reduces to 1/4th of the original (since folding halves the length and width: (70/2) × (56/2) = 35 × 28 cm).
2) The unfolded sheet maintains full area (70 × 56 cm).
3) Air pressure $P = F/A$, where F remains constant (same weight of chart paper), but A changes.
4) Pressure ratio = $\frac{P_{\text{unfolded}}}{P_{\text{folded}}} = \frac{F/A_{\text{unfolded}}}{F/A_{\text{folded}}} = \frac{A_{\text{folded}}}{A_{\text{unfolded}}}$
5) Calculation: $\frac{35×28}{70×56} = \frac{980}{3920} = \frac{1}{4}$
Thus, the pressure ratio is 1:4.

Key Concept: Air Pressure Experiment

c) The unfolded chart paper has a larger surface area exposed to atmospheric pressure
[Solution Description]
When the unfolded chart paper covers the paper plate, it increases the surface area exposed to atmospheric pressure. Air exerts force per unit area (pressure) on all objects. The larger area of the unfolded sheet means more air pressure acts downward, making it harder to lift. The folded sheet has less area, so less air pressure acts on it, requiring less effort.

Key Concept: SI Unit of Pressure

c) Pascal (Pa)
[Solution Description]
The SI unit of pressure is newton per square meter ($N/m^2$), also called pascal (Pa). Other units like millibar (mb) or hectopascal (hPa) are derived from it, where 1 mb = 100 Pa and 1 hPa = 100 Pa. The question tests recall of the fundamental unit.

Key Concept: Pressure and Area Relationship

b) Atmospheric pressure exerts a force proportional to the area exposed
[Solution Description]
Since the weight of the covering sheets remains constant but the effort varies with area, the increase in effort must be due to air pressure. Pressure ($P$) is force ($F$) per unit area ($A$), given by $P = F/A$. Larger area means more total force from atmospheric pressure acting downward, hence greater lifting effort.

Key Concept: Effect of air pressure on balloons

c) The balloon inflates because air exerts pressure on its walls.
[Solution Description]
When air is blown into a balloon, it gets inflated because the air exerts pressure on the inner walls of the balloon. This pressure acts in all directions, causing the balloon to expand uniformly.

Key Concept: Air movement due to pressure difference

c) Air moves from high-pressure regions to low-pressure regions.
[Solution Description]
In Activity 6.5, air moves from the inflated balloon to the uninflated one because the air pressure inside the inflated balloon is higher than that in the uninflated balloon. Air flows from a region of high pressure to a region of low pressure until the pressures equalize.

Key Concept: Pressure Exerted by Air

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that when air is blown between two inflated balloons, they move towards each other. This is true because, as demonstrated in Activity 6.6, blowing air between the balloons creates a low-pressure area between them. The higher air pressure outside the balloons then pushes them towards the low-pressure region, causing them to move closer.
The Reason correctly explains the Assertion, as it describes the phenomenon of high air pressure moving towards low air pressure, which causes the balloons to move towards each other. Therefore, both the Assertion and Reason are true, and the Reason is the correct explanation of the Assertion.

Key Concept: Direction of Air Pressure

c) Air exerts pressure equally in all directions, causing uniform expansion.
[Solution Description]
Air molecules inside the balloon move randomly and collide with the inner walls, exerting pressure uniformly in all directions. Since the rubber material of the balloon is flexible, it expands outward equally to balance the internal air pressure.

Key Concept: Atmospheric pressure, Suction cup

d) The air inside is at higher pressure than the surrounding atmosphere.
[Solution Description]
The air inside the balloon is at higher pressure than the atmospheric pressure outside. Air always moves from high-pressure regions to low-pressure regions. Hence, when the balloon's mouth is left open, the high-pressure air inside escapes to the lower-pressure surroundings until equilibrium is achieved.

Key Concept: Pressure-area relationship, Atmospheric force

d) Pressure exerts more force over larger areas.
[Solution Description]
When unfolded, the chart paper has a larger surface area exposed to atmospheric pressure. Since pressure is force per unit area ($P = F/A$), a larger area means greater total force exerted by atmospheric pressure downward, requiring more effort to lift the plate. This demonstrates that atmospheric pressure acts over surfaces, and its effect scales with area.

Key Concept: Pressure Difference

c) The difference in air pressure inside and outside the sucker creates a strong sticking force.
[Solution Description]
When the rubber sucker is pressed against a smooth surface, most of the air trapped inside its cup is pushed out. This reduces the internal air pressure compared to the atmospheric pressure outside. The higher external air pressure presses the sucker firmly onto the surface, making it difficult to pull off.

Key Concept: Air Pressure's Role in Daily Life

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that a rubber sucker sticks to a smooth surface because of the difference in air pressure, which is correct. When the sucker is pressed against a smooth surface, most of the air inside is pushed out, reducing the internal pressure. The external atmospheric pressure, being higher, exerts a force that keeps the sucker firmly attached to the surface. The reason correctly explains why this happens: it describes the process of expelling air from inside the sucker, creating a low-pressure region, and how the higher external pressure maintains the attachment. Therefore, both the assertion and reason are true, and the reason is the correct explanation of the assertion.

Key Concept: Pressure difference and wind direction

c) Difference in air pressure between regions
[Solution Description]
Air moves from a region of high pressure to a region of low pressure due to the pressure difference between the two regions. This movement of air is what we perceive as wind.

Key Concept: Formation of Wind, Pressure Difference, Land and Sea Breeze

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
During the day, land gets heated faster than water, causing the air above it to warm up and rise, creating a low-pressure area. The sea remains cooler, maintaining higher pressure. According to the principle of pressure difference, air flows from the high-pressure region (sea) to the low-pressure region (land), resulting in a sea breeze. The reason correctly explains the assertion because it highlights the fundamental principle that governs the movement of air, which is the pressure gradient.

Key Concept: Thunderstorms, Charge separation

c) Collision of water droplets and ice particles causes charge separation.
[Solution Description]
During thunderstorms, strong updrafts and downdrafts cause water droplets and ice particles to collide, leading to charge separation. Positive charges accumulate at the top and negative charges at the bottom of clouds. When the charge difference becomes large enough, it discharges as lightning.

Key Concept: Sea breeze and land breeze

d) Low pressure develops over the sea
[Solution Description]
During the day, the land heats up faster than the sea, causing the air above the land to become warmer and rise, creating a low-pressure area. The cooler air from the high-pressure area over the sea moves towards the land, resulting in a sea breeze.

Key Concept: Units of Pressure

c) Newton per cubic meter ($N/m^3$)
[Solution Description]
Air pressure can be measured in pascals ($Pa$), millibars ($mb$), or hectopascals ($hPa$). Newtons per cubic meter ($N/m^3$) measures density, not pressure.

Key Concept: Land and Sea Breeze

c) Because the sea is at a lower pressure than the land
[Solution Description]
At night, the land cools faster than the sea, resulting in higher pressure over the land compared to the sea. Air moves from the high-pressure land region to the low-pressure sea region, forming a land breeze.

Key Concept: Assertion-Reason

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that wind moves from a high-pressure region to a low-pressure region, which is true as explained in the activity where air flows from the inflated balloon (high pressure) to the uninflated balloon (low pressure). The Reason correctly explains this phenomenon by stating that the difference in air pressure causes the movement of air. Therefore, both Assertion and Reason are true, and Reason provides the correct explanation for the Assertion.

Key Concept: Pressure difference, Wind speed

b) 0.5 N
[Solution Description]
The force exerted by the air can be calculated using the pressure difference and the area of the straw. First, convert the pressures to pascals: $P_1 = 1100 \text{ mb} = 1100 \times 100 \text{ Pa} = 110000 \text{ Pa}$, $P_2 = 1050 \text{ mb} = 105000 \text{ Pa}$. The pressure difference is $\Delta P = P_1 - P_2 = 5000 \text{ Pa}$. Using the formula for pressure, $Force = \Delta P \times Area = 5000 \times 10^{-4} = 0.5 \text{ N}$.

Key Concept: Pressure difference and wind speed

d) Higher pressure difference increases wind speed.
[Solution Description]
Wind speed depends on the pressure gradient (difference in pressure) between two regions. A larger pressure difference ($\Delta P$) results in a stronger force pushing the air from the high-pressure region to the low-pressure region, which increases the wind speed. Conversely, a smaller pressure difference leads to slower wind speeds.

Key Concept: Land breeze formation

d) Cooler air sinks over the land, creating a high-pressure zone that pushes air towards the sea.
[Solution Description]
At night, the land cools down faster than the sea. As a result, the air above the land becomes cooler and denser, leading to a high-pressure area over the land. Meanwhile, the sea retains heat longer, keeping its surface warmer. The cooler air from the high-pressure land area moves towards the lower pressure over the sea, creating a land breeze.

Key Concept: Sea breeze, Land breeze

c) Due to the differential heating and cooling rates of land and sea.
[Solution Description]
During the day, the land heats up faster than the sea, causing the air above the land to rise (creating low pressure). Cooler air from the sea moves towards the land (sea breeze). At night, the land cools faster than the sea, so the warmer air over the sea rises (low pressure), and cooler air from the land moves towards the sea (land breeze).

Key Concept: Sea breeze and land breeze

b) Sea breeze
[Solution Description]
During the day, the land heats up faster than the sea, causing the warm air above the land to rise and create a low-pressure area. The cooler air from the sea (high-pressure area) moves towards the land, resulting in a sea breeze.

Key Concept: Land Breeze

c) The land cools down faster than the sea, causing air to move from the land to the sea.
[Solution Description]
At night, the land cools down faster than the sea. The air above the sea becomes warmer and rises, creating a low-pressure area. The cooler, high-pressure air from the land moves towards the sea, resulting in a land breeze.

Key Concept: Sea Breeze, Land Breeze, Wind Speed

b) Sea breeze winds are stronger than land breeze winds
[Solution Description]
Wind speed is proportional to the pressure difference. Since the sea breeze has a higher pressure difference (3 hPa) compared to the land breeze (2 hPa), the wind speed during the sea breeze will be stronger. This aligns with the relationship $\text{Wind speed} \propto \text{Pressure difference}$.

Key Concept: Sea Breeze, Land Breeze, Pressure Differences

d) Assertion is false, but Reason is true.
[Solution Description]
Let's analyze both Assertion (A) and Reason (R):
1. **Assertion (A):** "During the day, wind blows from the sea to the land because the land is cooler than the sea."
- This is false. During the day, the land gets heated faster than the sea, making the air above the land warmer and lighter. This creates a low-pressure area over the land, causing wind (sea breeze) to blow from the high-pressure sea region to the low-pressure land region.
2. **Reason (R):** "At night, the land cools faster than the sea, creating a high-pressure area over the land."
- This is true. At night, the land loses heat faster than the sea, making the air above it cooler and denser, which leads to high pressure over the land. As a result, wind (land breeze) blows from the land to the sea where the pressure is lower.
Since Assertion (A) is false but Reason (R) is true, the correct option is the one stating this relationship.

Key Concept: Land Breeze

c) Because the sea retains heat longer and develops lower pressure.
[Solution Description]
At night, the land cools down faster than the sea. The air above the sea remains warmer, creating a low-pressure area over the sea. Consequently, the cooler air from the high-pressure region over the land moves towards the sea, forming a land breeze.

Key Concept: Bernoulli's principle, Airflow dynamics

c) Low pressure forms between them due to fast airflow
[Solution Description]
When air is blown between the balloons, the speed of airflow increases, creating a low-pressure region between the balloons (as per Bernoulli's principle). The surrounding higher-pressure air exerts a force on the outer surfaces of the balloons, pushing them towards each other. Hence, the movement occurs due to the pressure difference caused by high-speed airflow.

Key Concept: High-Speed Winds Result in Lowering of Air Pressure, Bernoulli's Principle

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that keeping doors and windows closed during a storm increases the likelihood of roofs blowing off. This is true because when high-speed winds pass over the roof, they create a low-pressure area above it (Bernoulli's principle). If the house remains airtight (doors/windows closed), the higher air pressure inside the house exerts an upward force on the roof, potentially causing it to blow off. The reason correctly explains this phenomenon using Bernoulli's principle, which relates high-speed winds ($v$) and reduced pressure ($P$): $P + \frac{1}{2} \rho v^2 = \text{constant}$. Thus, both assertion and reason are true, and the reason is the correct explanation for the assertion.

Key Concept: High-Speed Winds Result in Lowering of Air Pressure

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
According to the syllabus, high-speed winds blowing over a surface create a low-pressure area because the fast-moving air reduces the number of air molecules applying force per unit area. This explains why roofs may be blown off during storms when high-speed winds lower the pressure outside while higher pressure inside pushes upward. Therefore, the Assertion is true because high-speed winds indeed reduce air pressure, and the Reason correctly explains this phenomenon by describing how fast-moving air leads to fewer air molecules exerting pressure.

Key Concept: Effect of high-speed winds

c) The pressure difference created by high-speed winds lifts the leaves.
[Solution Description]
High-speed winds create a low-pressure area above the leaves. The higher air pressure below the leaves pushes them upwards, lifting them into the air.

Key Concept: High-Speed Winds and Air Pressure

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that high-speed winds blowing over a roof can cause it to be blown off, which is true based on the syllabus. The reason explains that this occurs because high-speed winds lower the air pressure above the roof, while the higher pressure inside the house pushes upward. Since both the assertion and reason are correct, and the reason directly explains the assertion, the correct answer is (a).

Key Concept: Practical Example of Low Pressure

c) The balloons move towards each other.
[Solution Description]
Blowing air between two balloons increases the wind speed in that region, creating a low-pressure area between them. The surrounding higher-pressure air pushes the balloons inward, causing them to come closer together. This illustrates how high-speed winds reduce pressure.

Key Concept: Pressure difference and storm damage

b) It balances indoor and outdoor air pressure
[Solution Description]
During a storm, high-speed winds over the roof create low pressure outside. If windows are closed, the higher pressure inside the house can push the roof upward, causing damage. Opening windows equalizes the pressure inside and outside, reducing the risk of roof damage.

Key Concept: High-speed winds and air pressure

b) Air pressure decreases
[Solution Description]
When high-speed winds blow over a surface, they create a region of lower air pressure because the fast-moving air reduces the pressure in that area. This is due to Bernoulli's principle, which states that increasing the speed of a fluid decreases its pressure.

Key Concept: Effect of High-Speed Wind on Air Pressure

c) The air pressure decreases.
[Solution Description]
When air is blown between the two balloons, it creates a region of high-speed wind, which reduces the air pressure in that area. The surrounding higher air pressure pushes the balloons towards each other. Thus, the air pressure between the balloons decreases.

Key Concept: Air Pressure, Bernoulli's Principle

c) The balloons will move towards each other at three times the original speed.
[Solution Description]
From the activity, we know that higher blowing force creates greater pressure difference, leading to faster movement of balloons. Since acceleration is directly proportional to the pressure difference, tripling the pressure difference from 5 Pa to 15 Pa will triple the acceleration. Therefore, new acceleration = 3 $\times$ 2 m/s$^2$ = 6 m/s$^2$.
The balloons will now move towards each other more rapidly.

Key Concept: High-Speed Winds Result in Lowering of Air Pressure

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that when air is blown between two balloons, they move towards each other, which aligns with the activity observations. The reason explains that this movement occurs due to the creation of a low-pressure zone between the balloons and higher surrounding pressure pushing them together. Both statements are true, and the reason correctly explains the assertion based on the principle that high-speed winds (blowing air) lower air pressure between the balloons, leading to their movement.

Key Concept: Effect of Blowing Harder

c) The balloons move towards each other more quickly.
[Solution Description]
Blowing harder increases the speed of the air moving between the balloons, reducing the air pressure further. As a result, the difference in pressure causes the balloons to move towards each other more quickly.

Key Concept: Impact of Pressure Differences on Structures

b) It reduces the pressure difference between inside and outside.
[Solution Description]
Keeping doors and windows open allows the high-speed wind to move through the house, reducing the pressure difference between the inside and outside. This prevents the roofs from being blown off due to excessive pressure difference.

Key Concept: Unit of Pressure

b) Pascal ($Pa$)
[Solution Description]
The SI unit of pressure is $N/m^2$, also known as pascal ($Pa$). Other units like millibar ($mb$) and hectopascal ($hPa$) are also used, but $Pa$ is the standard SI unit.

Key Concept: Pressure reduction, Wind speed

b) 98,900 Pa
[Solution Description]
Given:
- Initial pressure ($P_{\text{initial}}$) = $1.02 \times 10^5$ Pa
- Pressure reduction = 3% of initial pressure
Step 1: Calculate pressure reduction amount
$0.03 \times 1.02 \times 10^5 = 3060$ Pa
Step 2: Calculate new pressure
$1.02 \times 10^5 - 3060 = 0.9894 \times 10^5$ Pa = $98,940$ Pa
Therefore, the new pressure is approximately 98,900 Pa

Key Concept: Impact of pressure differences on structures

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
According to the syllabus, high-speed winds create low pressure over the roof while the air pressure inside the house remains higher when windows/doors are closed. This pressure difference exerts an upward force on the roof (Pressure = Force/Area). If the roof is weak, it may blow away. The Reason correctly explains why keeping windows/doors closed increases this pressure difference. Hence, both Assertion and Reason are true, and Reason is the correct explanation.

Key Concept: Local Names of Thunderstorms

b) Bordoisila
[Solution Description]
In Assam, thunderstorms are locally known as Bordoisila. Kalboishakhi is associated with West Bengal, Bihar, and Jharkhand, while Mango showers occur in Kerala, Karnataka, and Tamil Nadu.

Key Concept: Lightning Formation, Thunderstorms

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that lightning occurs when the charge buildup is sufficient to overcome air's insulating property, which is accurate as per the syllabus. The reason explains the mechanism where the negatively charged lower part of the cloud induces a positive charge on the ground, creating a potential difference that results in lightning. Since the reason correctly explains the cause of the phenomenon described in the assertion, both are true and the reason is the correct explanation.

Key Concept: Lightning

c) Lower part of the cloud (heavier water droplets)
[Solution Description]
In a thundercloud, heavier water droplets collect in the lower part of the cloud, accumulating negative charges. Lighter ice particles with positive charges remain suspended in the upper part of the cloud.

Key Concept: Thunderstorm conditions, Safety measures

c) Standing near a tall tree in an open field
[Solution Description]
Standing near a tall tree is unsafe because lightning tends to strike the tallest object in an area. Even if crouching in an open area is advised, proximity to tall objects increases the risk of being struck.

Key Concept: Formation of thunderstorms

c) Rubbing between water droplets and ice particles due to upward and downward winds
[Solution Description]
Strong winds blowing upwards and downwards cause rubbing between water droplets and ice particles, leading to static electric charge separation. The positively charged lighter ice particles move to the top of the cloud, while negatively charged heavier water droplets settle at the bottom.

Key Concept: Charge separation, Lightning formation, Cloud dynamics

c) The negatively charged lower part of the cloud induces a positive charge on the ground.
[Solution Description]
The negative charges accumulate in the lower part of the cloud due to heavier water droplets, while positive charges rise to the upper part. When the negative charge in the cloud induces a positive charge on the ground, the potential difference increases until it discharges as lightning.

Key Concept: Safety Measures During Cyclones

d) To equalize air pressure inside and outside the house
[Solution Description]
Keeping doors and windows open allows wind to flow through the house, reducing the pressure difference between the inside and outside. This minimizes the risk of the roof being blown away due to high pressure inside.

Key Concept: Formation of Storms, Cyclones

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that opening doors and windows during a storm reduces the risk of roofs being blown away by equalizing pressure inside and outside the house. This is true because high-speed winds lower the air pressure above the roof, creating a pressure difference between the inside and outside of the house. If the pressure difference is large enough, roofs may be blown away. Opening doors and windows allows air to flow through the house, balancing this pressure difference.
The reason explains that high-speed winds create a low-pressure area above the roof, which can cause the roof to lift if the pressure difference is significant. This is also correct and directly supports the assertion. Therefore, both Assertion and Reason are true, and Reason correctly explains the Assertion.

Key Concept: Role of Warm Air in Thunderstorms

c) It leads to condensation and cloud formation
[Solution Description]
Warm and moist air rises because it is lighter, creating a low-pressure area. Cooler air from surrounding high-pressure areas moves in to replace it, forming wind circulation. As the rising air expands and cools, moisture condenses into water droplets, leading to cloud formation. Eventually, these droplets merge and fall as rain, hail, or snow.

Key Concept: Role of Winds, Moisture, and Temperature

a) Warm air has lower pressure than cold air.
[Solution Description]
Warm air rises because it is less dense than cooler air. When land gets heated, the warm and moist air becomes lighter and creates a low-pressure area, causing it to rise. This rising motion sets up the wind circulation necessary for thunderstorm development.

Key Concept: Thunderstorm formation, Charge separation in clouds

d) Assertion is false, but Reason is true.
[Solution Description]
The Assertion claims that lightning occurs exclusively between a cloud and the ground due to maximum charge separation there, which is false. Lightning can occur within a cloud, between clouds, or between a cloud and the ground. The Reason correctly describes the charge distribution in a thundercloud but does not justify the Assertion, as it explains general charge separation, not ground-specific phenomena.

Key Concept: Charge Separation in Clouds

c) Friction between water droplets and ice particles creates opposite charges
[Solution Description]
Strong upward and downward winds cause friction between water droplets and ice particles, leading to static electric charges. Positively charged lighter ice particles move to the upper part of the cloud, while negatively charged heavier water droplets occupy the lower part. This results in charge separation.

Key Concept: Static charge development within clouds leading to lightning

d) Assertion is false, but Reason is true.
[Solution Description]
The Assertion states that lightning occurs only when a cloud is negatively charged at the bottom and the ground is positively charged. This is false because lightning can also occur within a single cloud (intra-cloud lightning) or between two different clouds (inter-cloud lightning). The Reason, however, is true as it correctly describes the process of charge separation in clouds due to the rubbing of water droplets and ice particles from strong winds.

Key Concept: Lightning safety measures, Static charge induction

d) They attract lightning due to charge induction
[Solution Description]
Tall objects and metallic conductors are more likely to be struck by lightning because they provide a path of least resistance for the discharge. The negatively charged base of the cloud induces a positive charge on such objects, increasing the risk of a lightning strike.

Key Concept: Static charge separation, Lightning mechanism

c) 10$^5$ V/m
[Solution Description]
The electric field strength ($E$) is calculated using the formula $E = \frac{V}{d}$, where $V$ is the potential difference and $d$ is the distance. Given $V = 10^8$ V and $d = 1$ km = $1000$ m, substitute the values:
$E = \frac{10^8}{1000} = 10^5 \text{ V/m}$

Key Concept: Static charge development, Lightning conductor

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The lightning conductor is designed to protect buildings by providing a low-resistance path for lightning to follow, safely directing the charge into the ground. The pointed end of the conductor helps ionize the air, reducing the insulating property of air and allowing easier discharge. Both the assertion and reason are true, and the reason correctly explains why the lightning conductor works as described in the assertion.

Key Concept: Charge Separation in Clouds

c) Rubbing between water droplets and ice particles due to wind movement
[Solution Description]
The charge separation in a thundercloud occurs due to the upward and downward movement of strong winds, which cause rubbing between water droplets and ice particles. This friction results in static electric charges. Positively charged lighter ice particles move upwards, while negatively charged heavier water droplets settle at the lower part of the cloud.

Key Concept: Charge Separation, Lightning Formation

c) Friction between water droplets and ice particles
[Solution Description]
The charge separation in clouds occurs due to the rubbing of ice particles and water droplets by strong upward and downward winds. The lighter ice particles gain a positive charge and move to the upper part of the cloud, while the heavier water droplets gain a negative charge and occupy the lower part. This creates a charge separation within the cloud.

Key Concept: Lightning Conductor, Charge Transfer

c) It provides a path for charges to flow into the ground
[Solution Description]
A lightning conductor is a metallic rod with one end pointed and placed higher than the building's highest point. The other end is buried deep in the ground. When lightning strikes, the conductor provides an easy path for the electric charges to flow directly into the ground, preventing damage to the building.

Key Concept: Lightning Mechanism

d) When the buildup of opposite charges exceeds air's insulation capacity
[Solution Description]
Lightning occurs when the buildup of opposite charges becomes very large, causing the insulating property of air to break down. A sudden flow of charges produces a bright flash of light, known as lightning. This can happen within a cloud, between clouds, or between clouds and the ground.

Key Concept: Cyclone impact, Storm surge

c) 1200 meters
[Solution Description]
First, calculate the effective rise in water level due to the storm surge: $8 \, \text{m} - 2 \, \text{m} = 6 \, \text{m}$.
The land slope is 0.5%, meaning for every 100 meters horizontally, the elevation changes by 0.5 meters. To find the horizontal distance $x$ where the elevation rises by 6 meters:
$0.005 = \frac{6}{x} \implies x = \frac{6}{0.005} = 1200 \, \text{meters}$

Key Concept: Cyclone formation, Pressure difference

b) $0.167 \, \text{hPa/km}$
[Solution Description]
The pressure gradient is calculated as the change in pressure divided by the distance over which this change occurs. Here, the pressure difference is $1000 \, \text{hPa} - 950 \, \text{hPa} = 50 \, \text{hPa}$. The distance is 300 km.
Therefore, the pressure gradient is:
$\frac{50 \, \text{hPa}}{300 \, \text{km}} = \frac{1}{6} \, \text{hPa/km} \approx 0.167 \, \text{hPa/km}$

Key Concept: Cyclone Formation

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
According to the syllabus, cyclones indeed form over warm ocean waters where warm, moist air rises, creating a low-pressure area. This is correctly explained by the fact that Earth's rotation (Coriolis effect) causes the moving air to spin, forming a cyclone. Both statements are true, and the reason accurately explains the assertion.

Key Concept: Cyclone Impact

c) Earthquakes due to wind pressure
[Solution Description]
Cyclones cause destruction through strong winds, storm surges, and heavy rains, but they do not typically trigger earthquakes.

Key Concept: Impact of Cyclones

d) Gradual weakening due to loss of moisture source
[Solution Description]
When a cyclone reaches land, its source of moist air from the ocean is cut off, causing it to weaken gradually. However, before weakening, cyclones can cause severe destruction, including storm surges flooding coastal areas, heavy rainfall leading to landslides, and contamination of freshwater sources due to saltwater intrusion.

Key Concept: Impact

c) Strong winds, heavy rain, and storm surges
[Solution Description]
When a cyclone reaches land, it loses its source of moist air and weakens, but before that, it causes destruction through strong winds, heavy rainfall, storm surges, and flooding. The text explains: "Once the cyclone reaches land, the source of moist air is cut off and it gradually loses its strength... Cyclones can be extremely destructive..."

Key Concept: Storm surge, Cyclone impact

c) Widespread flooding and saltwater intrusion.
[Solution Description]
A storm surge is a rapid rise in sea level caused by a cyclone's strong winds pushing water toward the shore. A 10-meter surge can flood coastal regions extensively, damaging infrastructure, contaminating freshwater sources, and causing loss of life due to drowning or structural collapse.

Key Concept: Cyclone Formation

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that cyclones lose strength over land due to the absence of warm, moist air, which is correct as per the syllabus. The Reason explains that warm ocean water provides heat and moisture to sustain cyclones, which is also accurate. Since the Reason correctly explains why cyclones weaken over land (due to the loss of this energy source), both statements are true and logically connected.

Key Concept: Formation of Cyclones

c) By heating the air, causing it to rise and form a low-pressure zone
[Solution Description]
Cyclones form over warm ocean waters when the moist air above the heated water rises. As it rises, the water vapour condenses into raindrops, releasing heat, which warms the air further and causes it to rise more. This creates a low-pressure area that draws in surrounding air, forming a cyclonic system.

Key Concept: Structure of a cyclone: Eye of the cyclone

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that the eye of a cyclone is a region of low atmospheric pressure, which is true as per the syllabus. The reason explains that the calm wind in the eye is due to descending air that warms up and suppresses cloud formation, which is also correct and provides the explanation for why the eye has calm winds. Therefore, both Assertion and Reason are true, and Reason is the correct explanation of Assertion.

Key Concept: Effects of Cyclones

c) Flooding caused by storm surges pushing seawater inland
[Solution Description]
Cyclones cause destructive effects such as storm surges, which push seawater inland, leading to flooding. Other impacts include heavy rainfall, landslides, blocked roads due to debris, power outages, and contamination of drinking water sources.

Key Concept: Safety Measures, High-speed winds

b) Constructing cyclone-resistant buildings
[Solution Description]
For cyclones with high wind speeds like 250 km/h, the most effective safety measures include early warning systems for evacuation and sturdy shelters to withstand the winds. Public awareness campaigns and timely IMD alerts are also crucial. Among the options, constructing cyclone-resistant buildings provides long-term protection against such high-speed winds.

Key Concept: Cyclone energy, atmospheric pressure

c) 0.167 m/s²
[Solution Description]
To solve:
1. Pressure difference = 1010 - 950 = 60 hPa = 6000 Pa
2. Radius = 30 km = 30,000 m
3. Pressure gradient force per unit mass = $\frac{\Delta P}{\rho \times r}$
4. Take air density $\rho$ ≈ 1.2 kg/m³
5. Calculation: $\frac{6000}{1.2 \times 30000} = \frac{6000}{36000} ≈ 0.167 m/s²$

Key Concept: Impact of Cyclones on Land, Flooding

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that storm surges from cyclones can flood coastal and inland areas due to high water walls. This is true because cyclones generate powerful winds that push seawater, creating storm surges as mentioned in the syllabus. The reason explains the mechanism behind storm surges, which aligns with the assertion. Hence, both are true, and the reason correctly explains the assertion.

Key Concept: Cyclone formation, storm surge impact

c) 3.0 meters
[Solution Description]
To solve this:
1. Storm surge height = 8 m
2. Coastal elevation = 5 m
3. Effective flood height = surge - elevation = 8 - 5 = 3 m
4. Water will spread inland with decreasing depth but for approximation in low-lying areas close to shore, we can consider similar depth.
5. Therefore, approximate floodwater depth would be 3 m.

Key Concept: Agricultural Impact

c) Makes soil less fertile
[Solution Description]
Seawater contains high levels of salt, which makes the soil less fertile when it intrudes into farmland. This reduces crop yields and negatively impacts agriculture.

Key Concept: Collaborative efforts, technology

d) Combined resources and shared data improve tracking accuracy and warning systems.
[Solution Description]
International collaborations pool resources, expertise, and global satellite data to improve cyclone tracking accuracy. For example, sharing meteorological data from multiple countries helps in better modeling cyclone paths and issuing early warnings, reducing response time and increasing preparedness.

Key Concept: Eye of the cyclone

b) Low pressure and calm winds
[Solution Description]
The eye of a cyclone is the region of lowest pressure at the center, where winds are calm, while the surrounding regions experience strong winds and heavy rainfall.

Key Concept: Cyclone Monitoring

b) Weather monitoring satellites
[Solution Description]
Weather monitoring satellites provide real-time data on cloud patterns, wind speeds, and pressure systems, enabling accurate tracking and prediction of cyclone paths. Doppler radar and weather stations also contribute, but satellites offer the most comprehensive coverage.

Key Concept: Cyclone monitoring, Prediction measures

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that IMD uses weather satellites to predict cyclone paths and intensity accurately. This is true as satellites provide critical data for monitoring cyclones. The Reason explains that satellites supply real-time data on atmospheric conditions necessary for tracking cyclones, which is also true. Moreover, the Reason correctly explains why satellites are used for cyclone prediction, as they provide essential parameters like wind speed and pressure. Hence, both statements are true, and the Reason is the correct explanation of the Assertion.