Key Concept: Pressure and Area

c) The pressure increases
[Solution Description]
Pressure is defined as $Pressure = \frac{Force}{Area}$. If the force remains constant and the area decreases, the denominator in the equation becomes smaller, resulting in an increase in pressure. Therefore, pressure increases when the area decreases for a constant force.

Key Concept: Atmospheric Pressure

c) Millibar (\$mb)
[Solution Description]
Atmospheric pressure is measured in various units, but one common practical unit is millibar (mb), which is equal to 100 pascals (Pa). Another unit is hectopascal (hPa), also equivalent to 100 Pa. Both are widely used in meteorology.

Key Concept: Pressure Calculation

c) \(50\ \mathrm{N/m^2}\)
[Solution Description]
To find the pressure, use the formula $P = \frac{F}{A}$. Here, $F = 150$ N and A = 3 \(\mathrm{m}^2\)
Step 1: Divide the force by the area: $\frac{150}{3} = 50$.
Step 2: The unit of pressure is \(\mathrm{N/m^2}\), so the answer is \(50\ \mathrm{N/m^2}\).

Key Concept: Comparative pressure analysis, multi-step reasoning

c) 5 times
[Solution Description]
Calculate pressures individually.
Flat brick:
$P_{flat} = \frac{10}{100 \times 10^{-4}} = 1000 \text{ Pa}$
Vertical brick:
$P_{vertical} = \frac{10}{20 \times 10^{-4}} = 5000 \text{ Pa}$
The ratio of pressures is:
$\frac{P_{vertical}}{P_{flat}} = \frac{5000}{1000} = 5$
Thus, the vertical brick exerts 5 times more pressure.

Key Concept: Multi-concept: Pressure calculation with unit conversion

b) 0.637 MPa
[Solution Description]
Force = 5 kN = 5000 N.
Radius of piston = $\frac{10\,cm}{2} = 5\,cm = 0.05\,m$.
Area = $\pi r^2 = \pi (0.05)^2 = 0.00785\,m^2$.
Pressure = $\frac{Force}{Area} = \frac{5000}{0.00785} ≈ 636,942\,Pa$.
Convert to MPa: $636,942\,Pa = 0.637\,MPa$.

Key Concept: Pressure Calculation

c) 40 Pa
[Solution Description]
Pressure is calculated using the formula $P = \frac{F}{A}$. Here, $F = 200\,N$ and $A = 5\,m^2$. Substituting the values, we get:
$P = \frac{200\,N}{5\,m^2} = 40\,N/m^2 = 40\,Pa$
Thus, the pressure is 40 Pa.

Key Concept: Pressure and Area Relationship

c) Assertion is true, but Reason is false.
[Solution Description]
The assertion is correct because a sharp knife has a smaller area of contact compared to a blunt one for the same force, which leads to higher pressure according to $P = \frac{F}{A}$. However, the reason is incorrect because pressure is inversely proportional to the area of contact for a given force, not directly proportional. Therefore, the assertion is true, but the reason is false.

Key Concept: Formula for Pressure

b) \(50\ \mathrm{N/m^2}\)
[Solution Description]
Pressure tells us how much force is acting on each unit area. Here, a force of 200 N is spread over an area of 4 square metres. To find the pressure, divide the force by the area. So, each square metre receives 50 N of force. Therefore, the pressure exerted is 50 pascals (Pa).

Key Concept: Pressure and Area

c) The sharp knife has a smaller edge area, increasing pressure
[Solution Description]
A sharp knife has a smaller edge area compared to a blunt knife. Pressure is calculated as $Pressure = \frac{Force}{Area}$. For the same applied force, a smaller area results in higher pressure, making it easier to cut through objects. The higher pressure allows the sharp knife to penetrate materials with less effort.

Key Concept: Effect of Sharpness on Cutting

b) A sharp knife has a smaller edge area, increasing pressure.
[Solution Description]
A sharp knife has a smaller edge area, which increases the pressure applied when cutting, making it easier to slice through materials. A blunt knife has a larger edge area, reducing the pressure and making cutting more difficult. $Pressure = \frac{Force}{Area}$ explains this relationship.

Key Concept: Pressure Directionality, Balloon Inflation

c) Air pressure acts equally in all directions.
[Solution Description]
Air inside the balloon exerts pressure uniformly in all directions. This is because gas molecules move randomly and collide with the inner walls of the balloon in every direction equally. As a result, the balloon expands symmetrically, demonstrating that air pressure is isotropic—it acts equally in all directions.

Key Concept: Pressure Exerted by Air

d) The atmospheric pressure exerts a greater force due to the larger area of the unfolded sheet.
[Solution Description]
The unfolded chart paper has a larger surface area exposed to atmospheric pressure than the folded one. The air exerts force on the sheet, and because pressure is force per unit area ($P = F/A$), a larger area means greater total force acting downward. Thus, more effort is required to overcome this increased force when lifting the plate.

Key Concept: Pressure units, conversion

c) 1,020 mb
[Solution Description]
Both hectopascal (hPa) and millibar (mb) are equal in magnitude: $1 \text{ hPa} = 1 \text{ mb}$.
Therefore, $1,020 \text{ hPa} = 1,020 \text{ mb}$.

Key Concept: Atmospheric pressure, directionality

c) An inflated balloon expands uniformly when more air is blown into it.
[Solution Description]
Air exerts pressure equally in all directions. An inflated balloon expands uniformly because the air inside pushes outward in all directions. This is a direct observation of omnidirectional pressure.

Key Concept: Sucker Experiment Analysis

c) External air pressure exceeds the reduced pressure inside the sucker.
[Solution Description]
When the sucker is pressed, air inside it is expelled, reducing internal pressure. The external atmospheric pressure ($P_{\text{atm}}$) becomes higher than the internal pressure, creating a net inward force ($F = P_{\text{atm}} \times A$). This pressure difference makes it difficult to pull the sucker off.

Key Concept: Activity-Based Question

d) Air exerts greater pressure on the larger area of the unfolded sheet
[Solution Description]
Air exerts force on the surface area in contact. Since the unfolded sheet has a larger area than the folded one, the total force (and thus pressure) acting on it increases, requiring more effort to lift.

Key Concept: Air Pressure Experiment

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that more effort is needed to lift the paper plate with an unfolded chart paper than a folded one, which matches observations from Activity 6.3. The reason explains this phenomenon by stating that air exerts pressure on the sheet's surface area, and since $\text{Pressure} = \frac{\text{Force}}{\text{Area}}$, a larger area increases the force exerted by air pressure. Therefore, both statements are true, and the reason correctly explains the assertion.

Key Concept: Air Pressure - Basic Concept

d) More air pressure acts on the larger surface area of the unfolded sheet
[Solution Description]
Unfolding the chart paper increases the surface area exposed to air pressure. Air exerts pressure on all surfaces, and a larger area means more force acts downward due to atmospheric pressure. Hence, lifting requires more effort to overcome this increased force. The weight of the sheet remains the same, but the pressure force increases with area ($P = F/A$ implies $F = PA$). Thus, the correct reasoning relates to the effect of increased area.

Key Concept: SI Unit of Pressure

c) Pascal (Pa)
[Solution Description]
The SI unit of pressure is newton per square meter ($N/m^2$), also called pascal (Pa). Other units like millibar (mb) or hectopascal (hPa) are derived from it, where 1 mb = 100 Pa and 1 hPa = 100 Pa. The question tests recall of the fundamental unit.

Key Concept: Air Pressure Experiment

c) The unfolded chart paper has a larger surface area exposed to atmospheric pressure
[Solution Description]
When the unfolded chart paper covers the paper plate, it increases the surface area exposed to atmospheric pressure. Air exerts force per unit area (pressure) on all objects. The larger area of the unfolded sheet means more air pressure acts downward, making it harder to lift. The folded sheet has less area, so less air pressure acts on it, requiring less effort.

Key Concept: Pressure equilibrium

d) The air pressure in both balloons becomes equal.
[Solution Description]
The air flow stops when the pressure inside both balloons becomes equal. Initially, air flows from the inflated (high-pressure) balloon to the uninflated (low-pressure) balloon. Once the pressures balance, there is no further net movement of air, and both balloons reach nearly the same size.

Key Concept: Pressure gradient application

d) Air would flow until pressures equalize, with the balloon shrinking noticeably.
[Solution Description]
The inflated balloon's high-pressure air would flow into the rigid container (which initially has lower pressure) until pressures equalize. Since the container cannot expand, the balloon would shrink significantly while the container's pressure increases minimally due to its large volume. The final sizes wouldn't equalize unlike with two balloons.

Key Concept: Air movement due to pressure difference

c) Air moves from high-pressure regions to low-pressure regions.
[Solution Description]
In Activity 6.5, air moves from the inflated balloon to the uninflated one because the air pressure inside the inflated balloon is higher than that in the uninflated balloon. Air flows from a region of high pressure to a region of low pressure until the pressures equalize.

Key Concept: Pressure Exerted by Air

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that when air is blown between two inflated balloons, they move towards each other. This is true because, as demonstrated in Activity 6.6, blowing air between the balloons creates a low-pressure area between them. The higher air pressure outside the balloons then pushes them towards the low-pressure region, causing them to move closer.
The Reason correctly explains the Assertion, as it describes the phenomenon of high air pressure moving towards low air pressure, which causes the balloons to move towards each other. Therefore, both the Assertion and Reason are true, and the Reason is the correct explanation of the Assertion.

Key Concept: Pressure and Area

b) 10 $N/m^2$
[Solution Description]
The pressure exerted can be calculated using the formula: $P = \frac{F}{A}$. Here, $F = 50\;N$ and $A = 5\;m^2$. Substituting these values into the formula gives:
$P = \frac{50}{5} = 10\;N/m^2$
Therefore, the pressure exerted is 10 $N/m^2$.

Key Concept: Atmospheric Pressure

b) Narrow straps concentrate pressure on a smaller area
[Solution Description]
Broad straps increase the area over which the weight of the bag is distributed. Since pressure is defined as force per unit area ($P = \frac{F}{A}$), increasing the area reduces the pressure exerted on the shoulders. Therefore, carrying a bag with broad straps feels more comfortable because the pressure is spread out over a larger area.

Key Concept: Units of pressure, Real-world application

d) 100,000 Pa
[Solution Description]
First, convert mass to force: $F = mg = 225 \, \text{kg} \times 10 \, \text{m/s}^2 = 2250 \, \text{N}$. Then, convert area to square meters: $225 \, \text{cm}^2 = 0.0225 \, \text{m}^2$. Pressure $P = F/A = 2250 / 0.0225 = 100,\!000 \, \text{Pa}$ (or $1000 \, \text{hPa}$).

Key Concept: Assertion-Reason

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
When a sucker is pressed against a smooth surface, most of the air inside is expelled, creating a low-pressure region inside the sucker. The atmospheric pressure outside is much higher than the pressure inside the sucker, resulting in a net force pressing the sucker onto the surface. Thus, both Assertion and Reason are true, and Reason correctly explains the Assertion.

Key Concept: Thunderstorms, Charge separation

c) Collision of water droplets and ice particles causes charge separation.
[Solution Description]
During thunderstorms, strong updrafts and downdrafts cause water droplets and ice particles to collide, leading to charge separation. Positive charges accumulate at the top and negative charges at the bottom of clouds. When the charge difference becomes large enough, it discharges as lightning.

Key Concept: Pressure difference and wind formation

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that wind moves from high pressure to low pressure, which is correct as per Activity 6.5 where air moved from the inflated balloon (high pressure) to the uninflated balloon (low pressure). The reason is also true because air flows to equalize the pressure difference, as observed when both balloons attained the same size and air flow stopped. Moreover, the reason correctly explains the assertion since the movement of wind due to pressure differences is a fundamental concept in wind formation.

Key Concept: Formation of Wind

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that during the day, wind blows from the sea to the land because of the formation of a low-pressure region over the land. This is true as the land heats up faster than water, causing the air above it to warm up, rise, and create a low-pressure area. The Reason explains the cause of this phenomenon by stating that land gets heated faster, leading to the rising of air and creation of a low-pressure area. Since the Reason correctly explains the Assertion, both are true and logically connected.

Key Concept: Pressure difference and wind direction

c) Difference in air pressure between regions
[Solution Description]
Air moves from a region of high pressure to a region of low pressure due to the pressure difference between the two regions. This movement of air is what we perceive as wind.

Key Concept: Pressure Difference and Wind Formation

d) The flow of air increases
[Solution Description]
The speed of wind is directly proportional to the pressure difference between two regions. A higher pressure difference results in faster wind movement as air flows from high-pressure to low-pressure regions until equilibrium is reached.

Key Concept: Bernoulli's principle, Wind speed

c) 57.7 m/s
[Solution Description]
Using Bernoulli's equation, the pressure difference $\Delta P = \frac{1}{2} \rho v^2$. Convert $\Delta P$ to pascals: $1000 \text{ mb} - 980 \text{ mb} = 20 \text{ mb} = 2000 \text{ Pa}$. Rearranging for $v$: $v = \sqrt{\frac{2 \Delta P}{\rho}} = \sqrt{\frac{4000}{1.2}} \approx 57.7 \text{ m/s}$.

Key Concept: Assertion-Reason

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that wind moves from a high-pressure region to a low-pressure region, which is true as explained in the activity where air flows from the inflated balloon (high pressure) to the uninflated balloon (low pressure). The Reason correctly explains this phenomenon by stating that the difference in air pressure causes the movement of air. Therefore, both Assertion and Reason are true, and Reason provides the correct explanation for the Assertion.

Key Concept: Units of Pressure

c) Newton per cubic meter ($N/m^3$)
[Solution Description]
Air pressure can be measured in pascals ($Pa$), millibars ($mb$), or hectopascals ($hPa$). Newtons per cubic meter ($N/m^3$) measures density, not pressure.

Key Concept: Thunderstorms, Pressure difference

d) The pressure difference between outside and inside the house lifts the roof.
[Solution Description]
High-speed winds create a low-pressure area above the roof. The pressure inside the house remains higher, creating a pressure difference. If this difference is large enough and the roof is weak, it can be blown away. Keeping windows open equalizes the pressure.

Key Concept: Pressure difference, Wind speed

c) The wind speed doubles.
[Solution Description]
The wind speed is directly proportional to the pressure difference:
$\text{Wind speed} \propto \text{Pressure difference}$.
Initially, let the wind speed be $v_1$ when pressure difference is 12 hPa.
When pressure difference doubles to 24 hPa, the new wind speed $v_2$ can be calculated as:
$\frac{v_2}{v_1} = \frac{24 \text{ hPa}}{12 \text{ hPa}} = 2$
Therefore, $v_2 = 2v_1$. The wind speed doubles.

Key Concept: Land breeze formation

d) Cooler air sinks over the land, creating a high-pressure zone that pushes air towards the sea.
[Solution Description]
At night, the land cools down faster than the sea. As a result, the air above the land becomes cooler and denser, leading to a high-pressure area over the land. Meanwhile, the sea retains heat longer, keeping its surface warmer. The cooler air from the high-pressure land area moves towards the lower pressure over the sea, creating a land breeze.

Key Concept: Formation of Wind, Pressure Differences

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that during the day, sea breeze occurs due to warm air rising over the land, creating a low-pressure area, which causes cooler air from the sea (high-pressure area) to move toward the land. This is correct as per the concept of pressure differences in wind formation. The reason explains the general principle that air moves from high-pressure regions to low-pressure regions until equilibrium is reached, which directly explains why the sea breeze occurs. Both are true, and the reason correctly explains the assertion.

Key Concept: Pressure Differences, Sea Breeze

b) 1007 hPa
[Solution Description]
During the day, land heats up faster than the sea, creating a low-pressure area over the land. The cooler air over the sea has higher pressure, causing a sea breeze. Since the land pressure is given as 1005 hPa (low pressure), the sea pressure must be higher. Typically, pressure differences for sea breezes range between 2-4 hPa. Thus, the sea pressure is approximately 1007 hPa to 1009 hPa.

Key Concept: Sea Breeze and Pressure Differences

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that during the day, the wind blows from the sea to the land because the land is warmer than the sea. This is true as per the syllabus, which explains that during the day, the land becomes warmer and lighter, creating a low-pressure area. The reason given is that the land heats up faster than the sea during the day, creating a low-pressure region over the land. This is also true and correctly explains why the wind blows from the high-pressure sea to the low-pressure land, resulting in a sea breeze. Therefore, both the assertion and the reason are true, and the reason is the correct explanation of the assertion.

Key Concept: Sea Breeze, Land Breeze, Pressure Differences

d) Assertion is false, but Reason is true.
[Solution Description]
Let's analyze both Assertion (A) and Reason (R):
1. **Assertion (A):** "During the day, wind blows from the sea to the land because the land is cooler than the sea."
- This is false. During the day, the land gets heated faster than the sea, making the air above the land warmer and lighter. This creates a low-pressure area over the land, causing wind (sea breeze) to blow from the high-pressure sea region to the low-pressure land region.
2. **Reason (R):** "At night, the land cools faster than the sea, creating a high-pressure area over the land."
- This is true. At night, the land loses heat faster than the sea, making the air above it cooler and denser, which leads to high pressure over the land. As a result, wind (land breeze) blows from the land to the sea where the pressure is lower.
Since Assertion (A) is false but Reason (R) is true, the correct option is the one stating this relationship.

Key Concept: Pressure Differences

c) Wind moves from high-pressure areas to low-pressure areas.
[Solution Description]
Wind is caused by the movement of air from a region of high pressure to a region of low pressure. This principle explains phenomena like sea and land breezes.

Key Concept: Pressure equalization, Wind effects on structures

b) To reduce the pressure difference between inside and outside
[Solution Description]
When high-speed winds blow over a house, they create a low-pressure region above the roof. If the windows are tightly shut, the pressure inside the house remains higher compared to the outside, creating a significant pressure difference. This can cause the roof to lift or blow away. By keeping windows and doors slightly open, the wind flows through the house, reducing the pressure difference between the inside and outside, thereby minimizing structural damage.

Key Concept: High-Speed Winds Result in Lowering of Air Pressure, Bernoulli's Principle

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that keeping doors and windows closed during a storm increases the likelihood of roofs blowing off. This is true because when high-speed winds pass over the roof, they create a low-pressure area above it (Bernoulli's principle). If the house remains airtight (doors/windows closed), the higher air pressure inside the house exerts an upward force on the roof, potentially causing it to blow off. The reason correctly explains this phenomenon using Bernoulli's principle, which relates high-speed winds ($v$) and reduced pressure ($P$): $P + \frac{1}{2} \rho v^2 = \text{constant}$. Thus, both assertion and reason are true, and the reason is the correct explanation for the assertion.

Key Concept: High-speed winds, Pressure difference, Structural safety

b) 100365 Pa
[Solution Description]
According to Bernoulli's principle, the total energy per unit volume remains constant. The pressure difference can be calculated using the formula $\Delta P = \frac{1}{2}\rho v^2$. Given $\rho = 1.2$ kg/m$^3$ and $v = 40$ m/s, we have:
Step 1: Compute $\frac{1}{2}\rho v^2$
$\frac{1}{2} \times 1.2 \times (40)^2 = 0.6 \times 1600 = 960$ Pa.
Step 2: Subtract this from the internal pressure
Pressure above roof $= P_{\text{inside}} - \Delta P = 101325 - 960 = 100365$ Pa.
Thus, the pressure above the roof is approximately $100365$ Pa.

Key Concept: Bernoulli's principle, Airflow dynamics

c) Low pressure forms between them due to fast airflow
[Solution Description]
When air is blown between the balloons, the speed of airflow increases, creating a low-pressure region between the balloons (as per Bernoulli's principle). The surrounding higher-pressure air exerts a force on the outer surfaces of the balloons, pushing them towards each other. Hence, the movement occurs due to the pressure difference caused by high-speed airflow.

Key Concept: High-speed winds, pressure difference

c) It reduces the pressure difference between the inside and outside of the house
[Solution Description]
High-speed winds create a low-pressure area above the roof due to Bernoulli's principle. If windows and doors are kept closed, the higher air pressure inside the house pushes upwards on the roof while the lower pressure outside pulls the roof upwards. This large pressure difference can cause the roof to blow off. Keeping windows and doors open allows wind to pass through the house, equalizing the pressure inside and outside, thus reducing the risk of roof damage.

Key Concept: Wind Speed and Pressure Relationship

b) Air pressure decreases due to fewer molecular collisions.
[Solution Description]
According to Bernoulli's principle, an increase in wind speed leads to a decrease in air pressure. When wind blows faster over a surface, the kinetic energy of the air molecules increases, causing fewer collisions per unit area, resulting in lower pressure in that region.

Key Concept: High-speed winds, Bernoulli's principle, Low-pressure areas

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that during a storm, keeping windows and doors closed increases the likelihood of the roof blowing off due to pressure difference. This is correct because high-speed winds reduce pressure above the roof as per Bernoulli's principle ($P + \frac{1}{2} \rho v^2 = \text{constant}$). The reason explains this phenomenon correctly by mentioning the low-pressure region created by high-speed winds and the resulting pressure imbalance. Since both the assertion and reason are true, and the reason correctly explains the assertion, the correct answer is option a).

Key Concept: Pressure Difference Due to High-Speed Winds

b) The high pressure inside the house pushes the roof up as low pressure forms outside.
[Solution Description]
During storms, high-speed winds pass over the roof, reducing the air pressure above it. The higher air pressure inside the house pushes upwards on the roof due to this pressure difference. If the pressure difference is large enough, it can lift and blow the roof off. This demonstrates how high-speed winds create low-pressure areas.

Key Concept: High-Speed Winds and Air Pressure

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that when air is blown between two inflated balloons, they move towards each other, which is observed in Activity 6.6. This happens because blowing air between the balloons increases wind speed in the gap, reducing air pressure (Bernoulli’s principle). The higher pressure outside then pushes the balloons together. The reason correctly explains why this occurs by linking high-speed wind to low pressure and the resulting pressure difference.

Key Concept: Air Pressure, Bernoulli's Principle

c) The balloons will move towards each other at three times the original speed.
[Solution Description]
From the activity, we know that higher blowing force creates greater pressure difference, leading to faster movement of balloons. Since acceleration is directly proportional to the pressure difference, tripling the pressure difference from 5 Pa to 15 Pa will triple the acceleration. Therefore, new acceleration = 3 $\times$ 2 m/s$^2$ = 6 m/s$^2$.
The balloons will now move towards each other more rapidly.

Key Concept: Bernoulli's Principle, Air Pressure

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
Step 1: Analyzing Assertion (A).
- The assertion states that when air is blown between two balloons, they move towards each other because of decreased pressure between them.
- From Activity 6.6, blowing air between two inflated balloons creates a region of lower pressure between them compared to the surrounding air pressure.
- The higher external pressure pushes the balloons together, confirming the assertion is true.
Step 2: Analyzing Reason (R).
- The reason refers to Bernoulli's principle, which states that an increase in fluid velocity decreases its pressure.
- In this experiment, blowing air increases its speed between the balloons, leading to lower pressure as per Bernoulli's principle.
- This directly explains why the balloons move towards each other, making the reason both true and the correct explanation of the assertion.
Conclusion: Both Assertion (A) and Reason (R) are true, and Reason (R) correctly explains Assertion (A).

Key Concept: Observation of Balloons

c) The balloons move towards each other.
[Solution Description]
When air is blown between the balloons, a low-pressure area is created between them. The higher air pressure from the surrounding areas pushes the balloons towards each other. This demonstrates that high-speed winds result in lower air pressure.

Key Concept: Unit of Pressure

b) Pascal ($Pa$)
[Solution Description]
The SI unit of pressure is $N/m^2$, also known as pascal ($Pa$). Other units like millibar ($mb$) and hectopascal ($hPa$) are also used, but $Pa$ is the standard SI unit.

Key Concept: Pressure reduction, Wind speed

b) 98,900 Pa
[Solution Description]
Given:
- Initial pressure ($P_{\text{initial}}$) = $1.02 \times 10^5$ Pa
- Pressure reduction = 3% of initial pressure
Step 1: Calculate pressure reduction amount
$0.03 \times 1.02 \times 10^5 = 3060$ Pa
Step 2: Calculate new pressure
$1.02 \times 10^5 - 3060 = 0.9894 \times 10^5$ Pa = $98,940$ Pa
Therefore, the new pressure is approximately 98,900 Pa

Key Concept: Bernoulli's Principle Application

c) The balloons move closer together due to reduced pressure between them
[Solution Description]
Blowing air between the balloons creates a low-pressure region in between. The higher pressure on the outer sides of the balloons pushes them toward each other. This demonstrates Bernoulli's principle, where increased air speed results in decreased pressure.

Key Concept: Activity Observation

c) The balloons move towards each other faster.
[Solution Description]
Blowing harder increases the speed of air between the balloons, creating an even lower pressure area between them. The higher surrounding air pressure pushes the balloons closer together at a faster rate.

Key Concept: Formation of Thunderstorms

c) Upward movement of warm, moist air leading to condensation and cloud formation
[Solution Description]
The primary cause for the formation of thunderstorms is the upward movement of warm, moist air leading to condensation and the development of clouds. This process creates charge separation in clouds due to friction between rising and descending air currents.

Key Concept: Thunderstorm Names

c) Kalboishakhi
[Solution Description]
In West Bengal, Bihar, and Jharkhand, local thunderstorms occurring before the monsoon are called Kalboishakhi. These storms help kharif crops grow by providing rain.

Key Concept: Formation of thunderstorms and lightning

b) Both Assertion and Reason are true, but Reason is NOT the correct explanation of Assertion.
[Solution Description]
The assertion states that lightning occurs due to the sudden flow of charges when the insulating property of air breaks down, which is correct as per the syllabus. The reason mentions that rapid heating of air around lightning causes expansion, resulting in thunder, which is also true as per the syllabus. However, the reason does not explain why lightning occurs but instead explains the phenomenon of thunder, which is a consequence of lightning. Therefore, both are true, but the reason is not the correct explanation of the assertion.

Key Concept: Lightning formation, Charge separation

d) Strong winds rubbing against each other
[Solution Description]
The charge separation in thunderclouds is caused by strong winds rubbing against each other, creating static electric charges. Positively charged ice particles move upwards while negatively charged water droplets remain in the lower part of the cloud. This separation builds up until a discharge (lightning) occurs.

Key Concept: Formation of Storms

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that high-speed winds create a low-pressure area over houses, which is true as per the syllabus. The reason explains that this happens because high-speed winds are accompanied by reduced air pressure, which is also true and correctly explains why low pressure is created. Hence, both the assertion and reason are true, and the reason is the correct explanation of the assertion.

Key Concept: Formation of thunderstorms

c) Rubbing between water droplets and ice particles due to upward and downward winds
[Solution Description]
Strong winds blowing upwards and downwards cause rubbing between water droplets and ice particles, leading to static electric charge separation. The positively charged lighter ice particles move to the top of the cloud, while negatively charged heavier water droplets settle at the bottom.

Key Concept: Safety Measures During Cyclones

d) To equalize air pressure inside and outside the house
[Solution Description]
Keeping doors and windows open allows wind to flow through the house, reducing the pressure difference between the inside and outside. This minimizes the risk of the roof being blown away due to high pressure inside.

Key Concept: Thunderstorms and Lightning

d) Positive charges in the upper part and negative charges in the lower part
[Solution Description]
Before lightning, positive charges accumulate in the upper part of the cloud (ice particles), while negative charges (water droplets) collect in the lower part of the cloud.

Key Concept: Role of Warm Air in Thunderstorms

c) It leads to condensation and cloud formation
[Solution Description]
Warm and moist air rises because it is lighter, creating a low-pressure area. Cooler air from surrounding high-pressure areas moves in to replace it, forming wind circulation. As the rising air expands and cools, moisture condenses into water droplets, leading to cloud formation. Eventually, these droplets merge and fall as rain, hail, or snow.

Key Concept: Localized Thunderstorms

c) They supply necessary rain before monsoon for kharif crops.
[Solution Description]
Localized thunderstorms such as Kalboishakhi occur before the monsoon and provide essential rainfall that supports the growth of kharif crops and aids in ripening fruits like mangoes, benefiting agriculture.

Key Concept: Formation of Storms, Thunderstorms and Lightning

a) Warm air rises → Moisture condenses → Wind circulation → Charge separation → Lightning
[Solution Description]
First, warm moist air rises, creating a low-pressure area. Cooler air moves in to replace it, causing wind circulation. As the air rises, it cools, condenses into clouds, and forms water droplets. In thunderstorms, strong updrafts lift droplets to freezing heights, converting them to ice particles. Friction between these particles creates static charges, separating positive (top) and negative (bottom) charges in the cloud. When the charge difference becomes large enough, air's insulating property breaks down, causing a sudden discharge (lightning).

Key Concept: Concept: Formation of Thunderstorms

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
When land is heated, warm and moist air rises, creating a low-pressure area. As this air rises, it expands and cools, causing the moisture in it to condense and form clouds. This process can lead to the development of thunderstorms when strong winds and charge separation occur within the clouds. Thus, both the Assertion and Reason are true, and the Reason correctly explains the Assertion.

Key Concept: Static charge development within clouds leading to lightning

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
According to the syllabus, strong winds cause rubbing between water droplets and ice particles in clouds, generating static electric charges. Lighter positively charged ice particles move upwards while heavier negatively charged water droplets occupy the lower part of the cloud, creating charge separation. When the charge buildup becomes large enough, it overcomes air's insulating property, causing a sudden discharge of electricity (lightning). Thus, both Assertion (A) and Reason (R) are true, and Reason correctly explains the occurrence of lightning as described in the syllabus.

Key Concept: Lightning formation

b) When static charges accumulate sufficiently to break down the insulating property of air
[Solution Description]
Lightning occurs when the build-up of opposite charges becomes large enough to overcome the insulating property of air, causing a sudden discharge of electricity.

Key Concept: Lightning types, Charge distribution

c) Collision of opposite charges inside a single cloud
[Solution Description]
Intra-cloud lightning occurs due to the collision of opposite charges within the same cloud. The positively charged ice particles accumulate at the top, while negatively charged water droplets gather at the bottom. When the charge buildup is sufficient, discharge occurs within the cloud.

Key Concept: Static charge separation, Lightning mechanism

c) 10$^5$ V/m
[Solution Description]
The electric field strength ($E$) is calculated using the formula $E = \frac{V}{d}$, where $V$ is the potential difference and $d$ is the distance. Given $V = 10^8$ V and $d = 1$ km = $1000$ m, substitute the values:
$E = \frac{10^8}{1000} = 10^5 \text{ V/m}$

Key Concept: Thunder Formation

b) Rapid heating and expansion of air caused by lightning
[Solution Description]
Thunder is produced when lightning rapidly heats the surrounding air, causing it to expand explosively. This expansion creates a shockwave that manifests as a loud sound known as thunder.

Key Concept: Lightning Mechanism

d) When the buildup of opposite charges exceeds air's insulation capacity
[Solution Description]
Lightning occurs when the buildup of opposite charges becomes very large, causing the insulating property of air to break down. A sudden flow of charges produces a bright flash of light, known as lightning. This can happen within a cloud, between clouds, or between clouds and the ground.

Key Concept: Lightning Formation

c) A sudden flow of charges occurs, producing lightning
[Solution Description]
When the charge separation in the cloud becomes significant, the insulating property of air breaks down, allowing a sudden flow of charges. This discharge produces a bright flash of light called lightning. Lightning can occur within a cloud, between clouds, or between a cloud and the ground.

Key Concept: Formation of Thunder

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that thunder is produced due to rapid expansion of air caused by the intense heat from lightning. According to the syllabus, thunder indeed results from the explosive expansion of air heated by lightning. The reason explains that lightning involves a sudden flow of electric charges, which heats the air. This directly supports the assertion because the mechanism described in the reason leads to the effect mentioned in the assertion. Thus, both statements are true, and the reason correctly explains the assertion.

Key Concept: Cyclone formation, Pressure difference

b) $0.167 \, \text{hPa/km}$
[Solution Description]
The pressure gradient is calculated as the change in pressure divided by the distance over which this change occurs. Here, the pressure difference is $1000 \, \text{hPa} - 950 \, \text{hPa} = 50 \, \text{hPa}$. The distance is 300 km.
Therefore, the pressure gradient is:
$\frac{50 \, \text{hPa}}{300 \, \text{km}} = \frac{1}{6} \, \text{hPa/km} \approx 0.167 \, \text{hPa/km}$

Key Concept: Eye of the Cyclone

c) Calm winds and low pressure
[Solution Description]
The eye of the cyclone is a region of calm winds and low pressure at the center of the storm, surrounded by intense winds and heavy rainfall.

Key Concept: Cyclone Impact

c) Earthquakes due to wind pressure
[Solution Description]
Cyclones cause destruction through strong winds, storm surges, and heavy rains, but they do not typically trigger earthquakes.

Key Concept: Eye of the Cyclone

b) Descending air in the eye suppresses wind activity.
[Solution Description]
The eye of the cyclone is the region of lowest pressure at the center where the ascending air stops rising and begins descending. This descending motion suppresses cloud formation and wind activity, resulting in calm conditions. Meanwhile, the surrounding regions experience strong winds and heavy rainfall due to the cyclonic circulation.

Key Concept: Impact of Cyclones

d) Gradual weakening due to loss of moisture source
[Solution Description]
When a cyclone reaches land, its source of moist air from the ocean is cut off, causing it to weaken gradually. However, before weakening, cyclones can cause severe destruction, including storm surges flooding coastal areas, heavy rainfall leading to landslides, and contamination of freshwater sources due to saltwater intrusion.

Key Concept: Basic Concept

c) Eye of the cyclone
[Solution Description]
The eye of the cyclone is the central region where the pressure is the lowest and winds are calm. This is mentioned in the text as: "In a cyclone, the region of lowest pressure is at the centre, known as the eye of the cyclone."

Key Concept: Cyclone Formation

c) Heating of ocean water leading to rising warm, moist air
[Solution Description]
Warm ocean water heats the air above it, making the air warm and moist. As this warm and moist air rises, the water vapor condenses into raindrops, releasing heat back into the atmosphere. This further warms the ascending air, causing it to rise even more. The process creates a low-pressure area, drawing in surrounding air.

Key Concept: Cyclone Formation, Eye of Cyclone

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that the eye of a cyclone has calm winds and clear skies due to descending warm air. This is true because the sinking air in the eye inhibits cloud formation, leading to clear conditions. The Reason explains that descending air increases pressure and reduces moisture, suppressing clouds. Both statements are true, and the Reason correctly explains the Assertion as the descending air's warming effect prevents condensation and cloud formation.

Key Concept: Effects of Cyclones

c) Flooding caused by storm surges pushing seawater inland
[Solution Description]
Cyclones cause destructive effects such as storm surges, which push seawater inland, leading to flooding. Other impacts include heavy rainfall, landslides, blocked roads due to debris, power outages, and contamination of drinking water sources.

Key Concept: Formation of Cyclones

b) Condensation of water vapor releasing heat
[Solution Description]
Cyclones form when warm, moist air rises from the ocean surface, causing water vapor to condense into raindrops and release latent heat. This further warms the surrounding air, creating a low-pressure system and initiating cyclonic circulation due to Earth's rotation.

Key Concept: Eye of the Cyclone

c) The area of low pressure at the center with calm winds
[Solution Description]
The eye of a cyclone is the central region where the atmospheric pressure is the lowest. It is characterized by calm winds and clear skies, while the surrounding areas experience high-speed winds and heavy rain.

Key Concept: Eye of the Cyclone

b) Low pressure with calm winds
[Solution Description]
The eye of a cyclone is the central region with the lowest pressure, characterized by calm winds and clear skies. This is because the air in the eye descends slightly, inhibiting cloud formation.

Key Concept: Cyclone energy, atmospheric pressure

c) 0.167 m/s²
[Solution Description]
To solve:
1. Pressure difference = 1010 - 950 = 60 hPa = 6000 Pa
2. Radius = 30 km = 30,000 m
3. Pressure gradient force per unit mass = $\frac{\Delta P}{\rho \times r}$
4. Take air density $\rho$ ≈ 1.2 kg/m³
5. Calculation: $\frac{6000}{1.2 \times 30000} = \frac{6000}{36000} ≈ 0.167 m/s²$

Key Concept: Impact of Cyclones on Land, Flooding

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The assertion states that storm surges from cyclones can flood coastal and inland areas due to high water walls. This is true because cyclones generate powerful winds that push seawater, creating storm surges as mentioned in the syllabus. The reason explains the mechanism behind storm surges, which aligns with the assertion. Hence, both are true, and the reason correctly explains the assertion.

Key Concept: Cyclone formation, storm surge impact

c) 3.0 meters
[Solution Description]
To solve this:
1. Storm surge height = 8 m
2. Coastal elevation = 5 m
3. Effective flood height = surge - elevation = 8 - 5 = 3 m
4. Water will spread inland with decreasing depth but for approximation in low-lying areas close to shore, we can consider similar depth.
5. Therefore, approximate floodwater depth would be 3 m.

Key Concept: Impact of Cyclones on Agriculture

c) Salt from seawater makes the soil less fertile, reducing crop yields.
[Solution Description]
When seawater floods agricultural land due to a cyclone, the high salt content in the water can make the soil less fertile. This reduces crop productivity for months or even years until the salt is washed away naturally or through human intervention such as soil treatment.

Key Concept: Cyclone Formation

c) Warm ocean waters with temperatures above $26.5^{\circ}$C
[Solution Description]
A cyclone forms when warm ocean water heats the air above it, causing it to rise and create a low-pressure zone. As the moist air rises, condensation releases heat, further lowering pressure and drawing in surrounding air. The Earth's rotation causes the air to spin, forming a cyclone. Therefore, warm ocean waters are crucial for cyclone formation.

Key Concept: Emergency preparedness, IMD alerts

c) Stay updated with IMD alerts, prepare emergency kits, and move to shelters when advised.
[Solution Description]
The first step is to stay updated with IMD warnings. Next, the community should ensure emergency kits are ready with essentials like food, water, and medicines. Finally, during the cyclone, they must move to designated shelters for safety. These steps align with the syllabus guidelines for cyclone preparedness.

Key Concept: Collaborative efforts, technology

d) Combined resources and shared data improve tracking accuracy and warning systems.
[Solution Description]
International collaborations pool resources, expertise, and global satellite data to improve cyclone tracking accuracy. For example, sharing meteorological data from multiple countries helps in better modeling cyclone paths and issuing early warnings, reducing response time and increasing preparedness.

Key Concept: Cyclone monitoring, Prediction measures

a) Both Assertion and Reason are true, and Reason is the correct explanation of Assertion.
[Solution Description]
The Assertion states that IMD uses weather satellites to predict cyclone paths and intensity accurately. This is true as satellites provide critical data for monitoring cyclones. The Reason explains that satellites supply real-time data on atmospheric conditions necessary for tracking cyclones, which is also true. Moreover, the Reason correctly explains why satellites are used for cyclone prediction, as they provide essential parameters like wind speed and pressure. Hence, both statements are true, and the Reason is the correct explanation of the Assertion.